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fredd [130]
4 years ago
8

A cell is built using two electrodes: What reaction occurs at the cathode?

Chemistry
1 answer:
Nezavi [6.7K]4 years ago
4 0
A is the answer your welcome 
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<span>Why did the Republicans decide not to select Burr as a candidate for vice president in the Election of 1804?</span>
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3 years ago
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Enter the appropriate symbol for an isotope of potassium-39 corresponding to the isotope notation AZX.
muminat
The notation is actually written in this way (shown in the attached picture). The X is the symbol of the element. So, for potassium, the symbol is K. The A represents the mass number of the isotope. In this case, that would be equal to 39. The Z represents the atomic number of potassium, which is 19. Therefore, the symbol for the isotope is:  ³⁹₁₉K

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3 years ago
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What is the net ionic equation for the precipitation reaction between BaCl2 and Na2SO4?
Tom [10]
BaCl2 + Na2SO4-----> 2NaCl + BaSO4(s)

net ionic equation- Ba+2 + SO4 -2 -----> BaSO4 (s)
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3 years ago
Explain how stagnant sulfureted water may greatly accelerate metallic corrosion. (See the Email Link in Moodle) | (7 marks)
slavikrds [6]

Answer:

sulfur promotes oxide-reduction reactions.

Explanation:

In stagnant water, some solutes tend to precipitate. When Sulfur precipitate and touch a metal, Sulfur is being reduced and the metal is oxidated. This depends of potential redox of each element.  

6 0
3 years ago
If a stock solution of 20.0 g of sugar per 100. ml of solution is available, how much of this stock is needed to prepare 10.0 ml
Vladimir79 [104]

You must use 2.50 mL of the concentrated solution to make 10.0 mL of the dilute solution.

We can use the dilution formula

<em>V</em>_1<em>C</em>_1 = <em>V</em>_2<em>C</em>_2

where

<em>V</em> represents the volumes and

<em>C</em> represents the concentrations

We can rearrange the formula to get

<em>V</em>_2 = <em>V</em>_1 × (<em>C</em>_1/<em>C</em>_2)

<em>V</em>_1 = 10.0 mL; <em>C</em>_1 = 5.00 g/100. mL

<em>V</em>_2 = ?; ____<em>C</em>_2 = 20.0 g/100. mL

∴ <em>V</em>_2 = 10.0 mL × [(5.00 g/100. mL)/(20.0 g/100. mL)] = 10.0 mL × 0.250

= 2.50 mL

3 0
3 years ago
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