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Vitek1552 [10]
1 year ago
13

Draw the molecules listed below and circle any functional groups present. Provide the following information for each molecule:Mo

lecule's NameMolecule's Structural Fomula (Drawing)Name of Functional Group(s) PresentDiethyl ether Acetic Acid Ethene Isopropyl Alcohol Ethanol
Chemistry
1 answer:
aksik [14]1 year ago
3 0

The question requires us to draw the structural formula, provide the name and highlight any functional groups for the compound: diethyl ether.

The molecule diethyl ether can be represented as it follows, with two ethyl groups (-CH2CH3) bonded to a oxygen atom:

Note that the functional group ether (R-O-R) is present in the structre and highlighted in blue in the image. The official name of diethyl ether is ethoxyethane.

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When driving a truck,is fuel crucial?
Natali [406]

Answer:

The answer is yes.

Explanation:

When driving any type of motorized vehicle, fuel is importatn. Fuel is what it runs on, so without it it wouldn't run. With trucks a lot more is needed because trucks are bigger, and tend to carry more than a little car does.

6 0
3 years ago
For the vaporization reaction Br2(l) → Br2(
oksian1 [2.3K]
    The  temperature  at   which  the  process  be   spontaneous  is  calculated  as  follows

delta  G  =  delta H  -T delta S

let  delta G  be =0

therefore  delta H- T  delta s =0

therefore  T=  delta  H/  delta  S
convert  31   Kj  to  J  =  31  x1000=  31000 j/mol

T=31000j/mol /93 j/mol.k =333.33K


3 0
3 years ago
Which particle often described as having very little or no mass since the mass number does not change when you add more and more
astra-53 [7]

Answer:

I wrote this answer to get points lol

Explanation:

7 0
3 years ago
A student dissolved 1.805g of a monoacidic weak base in 55mL of water. Calculate the equilibrium pH for the weak monoacidic base
yawa3891 [41]

Answer:

11.39

Explanation:

Given that:

pK_{b}=4.82

K_{b}=10^{-4.82}=1.5136\times 10^{-5}

Given that:

Mass = 1.805 g

Molar mass = 82.0343 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Moles= \frac{1.805\ g}{82.0343\ g/mol}

Moles= 0.022\ moles

Given Volume = 55 mL = 0.055 L ( 1 mL = 0.001 L)

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity=\frac{0.022}{0.055}

Concentration = 0.4 M

Consider the ICE take for the dissociation of the base as:

                                  B +   H₂O    ⇄     BH⁺ +        OH⁻

At t=0                        0.4                          -              -

At t =equilibrium     (0.4-x)                        x           x            

The expression for dissociation constant is:

K_{b}=\frac {\left [ BH^{+} \right ]\left [ {OH}^- \right ]}{[B]}

1.5136\times 10^{-5}=\frac {x^2}{0.4-x}

x is very small, so (0.4 - x) ≅ 0.4

Solving for x, we get:

x = 2.4606×10⁻³  M

pOH = -log[OH⁻] = -log(2.4606×10⁻³) = 2.61

<u>pH = 14 - pOH = 14 - 2.61 = 11.39</u>

5 0
3 years ago
How many valence electrons does an atom of rubidium (Rb atomic number 37) have? A.One B.Five C.Six D.37
nadezda [96]
Electronic configuration of Rb: 2.8.8.8.8.3
Valence electron is 3....
4 0
3 years ago
Read 2 more answers
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