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3 years ago

Which molecule, when added to a solution, would give the solution the highest pH?

1 answer:

8 0

The <span>molecule, when added to a solution, would give the solution the highest pH is KOH. This is because when KOH is in the solution, it will give a very strong basic properties due to the -OH and the K which is highly electropositive.</span>

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Complete the electron-dot structure of s-allylcysteine, showing all lone-pair electrons.

erastova [34]

The structural formula of <span>s-allylcysteine is shown in the picture (top figure). To create its Lewis structure, draw all its bonds between elements. Each single bond contains two electrons. There is an octet rule that must be obeyed by most elements. Each element should be surrounded with 8 electrons. The hydrogen is exempted of this rule. So, there are 4 lone pairs for the S atom, 1 lone pair for the N atom, and 2 lone pairs each for the 2 O atoms.</span>

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4 years ago

What is the formula of the ionic compound composed of element X^2+ and element Y^-3?

mihalych1998 [28]

Answer: X3Y2

Explanation:

The formula is

X has a valency of 2

Y has a valency of 3

So, we interchange the valencies

Therefore, the formula is

X3Y2

3 0

3 years ago

Express 1340000 in scientific notation

Katen [24]

1.34*10^6
Move the decimal 6 times to the left, it is a number 1-10

8 0

3 years ago

Read 2 more answers

Tristearin and stearic acid are insoluble in water. However, sodium stearate (soap) is soluble. Why is there this difference in

kupik [55]

Explanation:

Sodium stearate , is the soap , it a ionic compound , hence , can easily break to cation and anion , and therefore is soluble in water .It works on the principle of micelle formation .

Tristearin and stearic acid are fatty acids , and have are carboxyl group and have a very huge hydrocarbon chain , making it non polar in nature ,hence is is insoluble in water , since , water is a polar molecule .

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4 years ago

The mass of sodium chloride in (g) is 14.19 The volume of ammonia solution in (mL) is 36.15 Calculate the following: What is the

Svetach [21]

This is an incomplete question, here is a complete question.

A weighed amount of sodium chloride is completely dissolved in a measured volume of 4.00 M ammonia solution at ice temperature, and carbon dioxide is bubbled in. Assume that sodium bicarbonate is formed util the limiting reagent is entirely used up. the solubility of sodium bicarbonate in water at ice temperature is 0.75 mol per liter. Also assume that all the sodium bicarbonate precipitated is collected and converted quantitatively to sodium carbonate.

Data to be used for calculating the results

-The mass of sodium chloride in (g) is 14.19

-The volume of ammonia solution in (mL) is 36.15

Calculate the following: What is the theoretical yield of sodium bicarbonate in grams?

Answer : The theoretical yield of sodium bicarbonate in grams is, 20.4 grams.

Explanation :

First we have to calculate the moles of NaCl and $NH_3$ .

$\text{ Moles of }NaCl=\frac{\text{ Mass of }NaCl}{\text{ Molar mass of }NaCl}=\frac{14.19g}{58.5g/mole}=0.243moles$

$\text{ Moles of }NH_3=\text{ Concentration of }NH_3\times \text{ Volume of solution}=4.00M\times 0.3615L=1.446moles$

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction will be:

$NH_3+NaCl+CO_2+H_2O\rightarrow NaHCO_3+NH_4Cl$

From the balanced reaction we conclude that

As, 1 mole of $NaCl$ react with 1 mole of $NH_3$

So, 0.243 mole of $NaCl$ react with 0.243 mole of $NH_3$

From this we conclude that, $NH_3$ is an excess reagent because the given moles are greater than the required moles and $NaCl$ is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $NaHCO_3$

From the reaction, we conclude that

As, 1 mole of $NaCl$ react to give 1 mole of $NaHCO_3$

So, 0.243 moles of $NaCl$ react to give 0.243 moles of $NaHCO_3$

Now we have to calculate the mass of $NaHCO_3$

$\text{ Mass of }NaHCO_3=\text{ Moles of }NaHCO_3\times \text{ Molar mass of }NaHCO_3$

Molar mass of sodium bicarbonate = 84 g/mol

$\text{ Mass of }NaHCO_3=(0.243moles)\times (84g/mole)=20.4g$

Thus, the theoretical yield of sodium bicarbonate in grams is, 20.4 grams.

4 0

4 years ago