Pr

1 answer:

8 0

Yo necesito una reserva de café y una ensalada de café con queso queso y queso queso de naranja queso queso y queso queso de naranja queso y ensalada con un café y queso queso de naranja y una ensalada de café y ensalada de café de pescado con carne pescado con un vestido verde con queso y ensalada y queso de pescado queso y una ensalada de pescado y una ensalada de café y ensalada con queso y queso queso de naranja y queso de café y ensalada con carne de naranja y ensalada de pescado con carne y ensalada con carne y una ensalada de café y ensalada con un café y café café

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Solve pls brainliest

Alexxx [7]

Answer:

for the first one it 2

8 0

2 years ago

I NEED HELPPP AHHHHHH!!!!!!!!!!!!!!!!!!!!!!!!

Tju [1.3M]

5. complementary = 80 degrees
supplementary = 170 degrees

6. complementary = 47.5 degrees
supplementary = 137.5 degrees

7. complementary = 10 degrees
supplementary = 100 degrees

8. false
9. true
10. true
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12. false
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14. false

6 0

3 years ago

Read 2 more answers

Is 144 a perfect square or not

Rina8888 [55]

Answer: Yes

Step-by-step explanation: 144 is a perfect square. In other words, it's possible to find a whole number that can be multiplied by itself that gives us 144.

In this case, we multiply 12 by 12 or 12² to get 144 which means 144 is a perfect square. Also, it's on our perfect square list which I will attach below.

6 0

3 years ago

If the parent function f(x) = x^2 is fatter translated 11 units to the left, then translated 5 units down, write the resulting f

nikklg [1K]

The quadratic function given by:

$f(x)=a(x-h)^2+k, \ \ \ a\neq 0$

is in vertex form. The graph of $f$ is a parabola whose axis is the vertical line $x=h$ and whose vertex is the point $(h, k)$ . So:

To translate the graph of a function to the right, left, upward or downward we have:

$For \ a \ positive \ real \ number \ c. \ \mathbf{Vertical \ and \ horizontal \ shifts} \\ in \ the \ graph \ of \ y=f(x) \ are \ represented \ as \ follows:\\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{upward}: \\ g(x)=f(x)+c \\ \\ \bullet \ Vertical \ shift \ c \ units \ \mathbf{downward}: \\ g(x)=f(x)-c \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{right}: \\ g(x)=f(x-c) \\ \\ \bullet \ Horizontal \ shift \ c \ units \ to \ the \ \mathbf{left}: \\ g(x)=f(x+c)$

By knowing this things, we can solve our problem as follows:

FIRST.

Translating 11 units to the left:

$g(x)=f(x+11) \\ \\ \therefore g(x)=(x+11)^2$

Then translating 5 units down:

$g(x)=f(x)-c \\ \\ \therefore g(x)=(x+11)^2-5$

Since the new function is fatter, the factor we need to multiply the term $(x+11)^2$ must be less than 1, to make the graph fatter. So, according to our options, there are two factors 1/2 and 2.