We are given the function:
g(x) = 6 (4)^x
Part A.
To get the average rate of change, we use the formula:
average rate of change = [g(x2) – g(x1)] / (x2 – x1)
Section A:
average rate of change = [6 (4)^1 – 6 (4)^0] / (1 – 0) =
18
Section B:
average rate of change = [6 (4)^3 – 6 (4)^2] / (3 – 2) =
288
Part B.
288 / 18 = 16
Therefore the average rate of change of Section B is 16 times
greater than in Section A.
<span>The average rate of change is greater between x = 2 to x = 3 than between
x = 1 and x = 0 because an exponential function's rate of change increases
with increasing x (not constant).</span>
The coach can buy 16 uniforms with $4.50 left.
$475-6.50=$468.5÷29=16 R4.5
The answer for this would be 0.167
Answer:
128 boxes
Step-by-step explanation:
The dimensions of the trunk is 24 in. by 24 in by 48 in
The volume = 24(24)(48) = 27648 cu. in.
The cubed boxes each have a volume of 6(6)(6) = 216 cu. in.
27648/216 = 128 boxes
