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Aleksandr [31]
2 years ago
10

Isosceles triangle LMN is graphed with vertices L(0, 1), M(3, 5), and N(6,1). What is the slope of side LN?

Mathematics
2 answers:
AleksAgata [21]2 years ago
7 0

Answer:

0

Step-by-step explanation:

Hello

to find the slope  we must to know that the slope of a line is a number that measures its "steepness", usually denoted by the letter m. It is the change in y for a unit change in x along the line

m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\\

Let

m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\\

L ⇒ P1 (0,1)  

x_{1}=0 \\y_{1}=1

N⇒ P2(6,1)

x_{2}=6 \\y_{2}=1

m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\\\\m=\frac{1-1 }{6-0 }\\m=\frac{0}{6} \\m=0\\

m=0

which means that the line LN is horizontal

Have a great day

Lesechka [4]2 years ago
4 0
You would have to do the change in y over the change in x
1. 1-1/6-0
2. 0/6 and any time you divide zero by a number the answer is zero.
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Step-by-step explanation:

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Read 2 more answers
Hellpp please 20 points for that​
Sergio [31]

Answer:

a) 12cm

b) 360cm²

c) 2160cm cubed

Step-by-step explanation:

a)

you would use Pythagoras theorem  for A

so half of 18 is 9

15² - 9² = 144

the square root of 144 is 12

the height is 12cm

b)

18 x 20 = 360cm²

c)

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8 0
2 years ago
A box is being created out of a 15 inch by 10 inch sheet of metal. Equal-sized squares are cutout of the corners, then the sides
ivolga24 [154]

Answer:

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

Step-by-step explanation:

Given that,

A box is being created out of a 15 inches by 10 inches sheet of metal.

The length of the one side of the squares which are cut out of the each corners of the metal sheet be x.

The length of the metal box be = (15-2x) inches.

The width of the metal box be =(10-2x) inches

The height of the metal box be =x inches

Then, the volume of the metal box= length×width×height

                                                         =(15-2x)(10-2x)x cubic inches

                                                         =(150x-50x²+4x³) cubic inches

∴ V= 4x³-50x²+15x

Differentiating with respect to x

V'=12x²-100x+15

Again differentiating with respect to x

V''=24x-100

For maximum or minimum value, V'=0

12x²-100x+15=0

Apply quadratic formula x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}, here a=12, b= -100 and c=15

x=\frac{-(-100)\pm\sqrt{(-100)^2-4.12.15}}{2.12}

\Rightarrow x=\frac{100\pm\sqrt{9280}}{2.12}

\Rightarrow x=0.1528,8.18

For x= 8.18, The value of (15-2x) and (10-2x) will negative.

∴x=0.1528 .

Now, V''|_{x=0.1528}=24(0.1528)-100

∴At x=0.1528 inch, the volume of the metal box will be maximum.

Therefore the dimensions of the square should be 0.1528 inch by 0.1528 inch so, the box  has largest volume.

4 0
3 years ago
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