Since there is a flat membership fee of $18, the y intercept is 18. And since there is a $3 fee per number of video games rented, n, the slope or rate of change of the linear equation is 3. The slope-intercept form of a line is:
f(x)=mx+b, where m=slope and b=y-intercept so in terms of n, games rented, the cost, f(n) is:
f(n)=3n+18
Answer:
<h3> X=2 and x=4</h3>
Step-by-step explanation:
x+3>0 {or logarithm does'nt have a sense}
-4+3=-1 not >0 so the first two are out
-3+3=0 not >0 so the third also is out
2+3=5>0 and 4+3=7>0, so only the fourth could be the potential answer
Answer:
2
Step-by-step explanation:
By the triangle proportionality theorem,
From this, we know that y = -1/2 or 2.
However, as distance must be positive, we disregard the negative case, giving us y = 2.
<span>(a) This is a binomial
experiment since there are only two possible results for each data point: a flight is either on time (p = 80% = 0.8) or late (q = 1 - p = 1 - 0.8 = 0.2).
(b) Using the formula:</span><span>
P(r out of n) = (nCr)(p^r)(q^(n-r)), where n = 10 flights, r = the number of flights that arrive on time:
P(7/10) = (10C7)(0.8)^7 (0.2)^(10 - 7) = 0.2013
Therefore, there is a 0.2013 chance that exactly 7 of 10 flights will arrive on time.
(c) Fewer
than 7 flights are on time means that we must add up the probabilities for P(0/10) up to P(6/10).
Following the same formula (this can be done using a summation on a calculator, or using Excel, to make things faster):
P(0/10) + P(1/10) + ... + P(6/10) = 0.1209
This means that there is a 0.1209 chance that less than 7 flights will be on time.
(d) The probability that at least 7 flights are on time is the exact opposite of part (c), where less than 7 flights are on time. So instead of calculating each formula from scratch, we can simply subtract the answer in part (c) from 1.
1 - 0.1209 = 0.8791.
So there is a 0.8791 chance that at least 7 flights arrive on time.
(e) For this, we must add up P(5/10) + P(6/10) + P(7/10), which gives us
0.0264 + 0.0881 + 0.2013 = 0.3158, so the probability that between 5 to 7 flights arrive on time is 0.3158.
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