June and Armando are each in a hot air balloon. Armando's balloon is at a slightly higher elevation than June's. The two balloon
1 answer:
Answer:
46.63 ft
Step-by-step explanation:
I've drawn and attached a triangle diagram to represent this elevation and distance of balloons.
Now, from the diagram attached, we can see the angle at which June must look up to see Armando is 25°.
Also, the height of Armando above June is represented by "x".
Thus, using pythagoras theorem, we can find x.
Thus;
x/100 = tan 25
x = 100 × tan 25
x = 100 × 0.4663
x = 46.63 ft
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Answer:
C = $2.40
n = 6
Step-by-step explanation:
For Noelle,
Equation that represents the monthly cost 'C',
C = 0.2n + 1.20
Here, n = number of checks written in a month
For Micah,
Monthly cost for writing checks 'C' = $1.20
Number of checks 'n' = 3
Since, Cost of writing checks ∝ Number of checks written
C' ∝ n
C' = kn
k =
Here, k = proportionality constant
For C' = 1.2 and n = 3
k =
k = 0.4
Equation will be,
C' = 0.4n
For any month C = C'
Therefore, 0.2n + 1.20 = 0.4n
0.4n - 0.2n = 1.20
0.2n = 1.20
n = 6
Number of checks written by Noelle and Micah = 6
For n = 6,
C = 0.2(6) + 1.20
C = $2.40
Cost of writing checks = $2.40
Answer:
The probability that neither is available when needed
Step-by-step explanation:
A town has 2 fire engines operating independently
Given data the probability that a specific engine is available when needed is 0.96.
Let A and B are the two events of two fire engines
given P(A and B) = 0.96 ( given two engines are independent events so you have to select A and B)
Independent events : P( A n B) = P(A) P(B)
The probability that neither is available when needed
Answer:
(C)
Step-by-step explanation:
Given the distance, d(t) of a particle moving in a straight line at any time t is:
To find an expression for the instantaneous velocity v(t) of the particle at any given point in time, we take the derivative of d(t).
The correct option is C.