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2 years ago

Simplify the expression. 2(a-3)=

Mathematics

2 answers:

Dahasolnce [82]2 years ago

7 0

Answer:

2a - 6 =

Step-by-step explanation:

yeah-ya........ right?

Travka [436]2 years ago

4 0

(ik someone answered with the same answer but heres a more detailed answer)

2(a-3) =
To simplify distribute;
2xa - 3x2 =

Answer: 2a-6

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What is the range of the function f(x)=3/4x-3

kipiarov [429]

Answer:

(-∞,0)∪(0,∞)

Step-by-step explanation:

The domain of a function is wherever the y values exist. The only time the y values dont exist in this function is when the denominator is zero. So the denominator does not exist at x=0, because that is when 4x = 0.

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3 years ago

What does the numerator tell us in fraction

Katena32 [7]

For an example 3/5 is like i ate 3 of the 5 apples i had

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3 years ago

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What is an estimate for the square root of 150? (Do not find the exact value) Show work

Umnica [9.8K]

Answer:

Somewhere between 12 and 13, perhaps 12.25

Step-by-step explanation:

This is a (rather) simple explanation:

Look for 2 square numbers that are either side of 150

In this case, it is 144 and 169

The square root of 144 is 12 and the square root of 169 is 13

Therefore we can estimate that the square root of 150 is somewhere between 12 and 13.

As 150 is a lot closer to 144 to 169, I would estimate around 12.25 but you do not need an exact value :)

5 0

2 years ago

For the line segment whose endpoints are A (0, 0) and B (4, 3), find the x coordinate for the point located 2 over 3 the distanc

WARRIOR [948]

Answer:

Step-by-step explanation:

Distance between AB is expressed as;

AB = √(3-0)²+(4-0)²

AB = √3²+4²

AB =√9+16

AB = √25

AB = 5

2 over 3 the distance from A to B is expressed as;

2/3 of AB

= 2/3 * 5

=10/3

= 3.3

6 0

3 years ago

Read 2 more answers

Persons having Raynaud's syndrome are apt to suffer a sudden impairment of blood circulation in fingers and toes. In an experime

Citrus2011 [14]

Answer:

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

Step-by-step explanation:

We have to perform a hypothesis test on the difference between means.

The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a: \mu_1-\mu_2$

μ1: mean heat output for subjects with the syndrome.

μ2: mean heat output for non-sufferers.

We will use a significance level of 0.05.

The difference between sample means is:

$M_d=\bar x_1-\bar x_2=0.63-2.09=-1.46$

The standard error is

$s_{M_d}=\sqrt{\sigma_1^2/n_1+\sigma_2^2/n_2}=\sqrt{0.3^2/9+0.5^2/9}=\sqrt{ 0.038 } \\\\ s_{M_d}=0.194$

The t-statistic is

$t=\dfrac{M_d}{s_{M_d}}=\dfrac{-1.46}{0.194}=-7.52$

The degrees of freedom are

$df=n_1+n_2-2=9+9-2=16$

The critical value for a left tailed test at a significance level of 0.05 and 16 degrees of freedom is t=-1.746.

The t-statistic is below the critical value, so it lies in the rejection region.

The null hypothesis is rejected.

There is enough evidence to say that the true average heat output of persons with the syndrmoe differs from the true average heat output of non-sufferers.

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3 years ago