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scZoUnD [109]
2 years ago
13

A party rental company has chairs and tables for rent. The total cost to rent 6 chairs and 5 tables is $63. The total cost to re

nt 2 chairs and 3 tables is $35. What is the cost to rent each chair and each table?
Mathematics
1 answer:
tensa zangetsu [6.8K]2 years ago
6 0

Answer:

1.75dollars - the value of each chair,  10.5 dollars - the value of each table

Step-by-step explanation:

The value of chair is x, the value of table is y. Then 6chairs cost 6x, 5 tables cost 5y. 6x+5y= 63

Then the value of 2 chairs is  2x,  for 3 tables  it is equal to 3y. 2x+3y=35

We have the system of equations6x+5y= 63 and 2x+3y=35

Multiply the second one by -3

-3(2x+3y)= -3*35

-6x-9y= -105.

Plus the first equation and the second one multiplied by -3 (the right side to the right side and the left side to the left side with sign= between them)

6x+5y-6x-9y= 63-105

-4y= -42

y=10.5 dollars - the value of a table

6x+5*10.5=63

6x= 63-52.5

6x=10.5

x=1.75dollars - the value of a chair

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6 0
2 years ago
Consider the two data sets below:
alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

  • IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

             [19, 25, 35, 38],  41,  [49, 50, 52, 59]

                                         ↑

                                     median = 41

   

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

             [19, 25, 35, 38] , 41,  [49, 50, 52, 99]

                                         ↑

                                      median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

                [19, 25, 35, 38],

                            ↑

                           Q1 = [25 + 35] / 2 = 30

                   <u>Third quartile</u>

                   [49, 50, 52, 59]

                                ↑

                                Q3 = [50 + 52] / 2 = 51

                     IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

                   [19, 25, 35, 38]

                               ↑

                               Q1 = [25 + 35] / 2= 30

                  <u>Third quartile</u>

                   [49, 50, 52, 99]

                                ↑

                                Q3 = [52 + 50]/2 = 51

                   IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

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What is the median of the data?
eimsori [14]
<span>20, 19, 13, 23, 16, 15, 17, 17, 15, 15, 22, 19

</span>To find the Median, place the numbers in value order<span> and find the </span>middle<span>.
</span>
13, 15, 15, 15, 16, 17, 17, 19, 19, 20, 22, 23

There are 12 numbers and so we don't have just one middle number, we have a pair of middle numbers:


13, 15, 15, 15, 16, (17, 17), 19, 19, 20, 22, 23

<span>To find the value halfway between them, add them together and divide by 2:
</span>
17 + 17 = 34
34 ÷ 2 = 17

So the median is A) 17.

8 0
3 years ago
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