You can start by subtracting different equations from each other.
3x + 2y + 3z = 1
subtract
3x + 2y + z = 7
2z = -6
divide by 2
z = -3
add the following two expressions together:
3x + 2y + z = 7
3x + 2y + 3z =1
6x + 4y + 4z = 8
subtract the following two expressions:
6x + 4y + 4z = 8
5x + 5y + 4z = 3
x - y = 5
^multiply the whole equation above by 3
3x - 3y = 15
subtract the following two expressions:
3x - 3y = 15
3x + 2y = 10
-5y = 5
divide each side by -5
y=-1
take the following expression from earlier:
x - y = 5
substitute y value into above equation
x - - 1 = 5
2 negatives make a positive
x + 1 = 5
subtract 1 from each side
x = 4
Therefore x = 4, y = -1, z = -3
I checked these with all 3 equations and they worked :)
(it's quite complicated, comment if you don't understand anything) :)
Answer:
-274
Step-by-step explanation:
Answer:
The relationships are correct and valid
Step-by-step explanation:
The correct question is as follows;
Verify the following
i.[ -3/4]^3 = -27/64
ii. [-2/3]^6 = 64/ 729
We have the solution as follows;
i) we have;
(-3/4)^3
That means ;
-3^3 = -3^3 = -27
4^3 = 64
so;
(-3/4)^3 = -27/64
ii) (-2/3)^6
(-2)^6 = 64
3^6 = 729
Thus;
(-2/3)^6 = 64/729
12,000,000+400,000+30,000+
Answer:
Step-by-step explanation:
4(8+2n) = 4 + 4n
32 + 8n = 4+4n
4n = -28
n = -7
