Answer:
Domain: 1 ≤ x ≤ 4
Range : 1 ≤ f(x) ≤ 4
Step-by-step explanation:
The domain of a function f(x) is the limit within which the values of x varies.
Here, in the graph, it shows that the maximum value of x is 4 and the minimum value of x is 1.
Therefore, the domain of the function is 1 ≤ x ≤ 4
Again the range of a function f(x) is the limit within which the values of f(x) vary.
Here, the graph shows that the maximum value of f(x) is 4 and the minimum value of f(x) is 1.
Therefore, the range of the function f(x) is 1 ≤ f(x) ≤ 4. (Answer)
0.8-0.45=0.35
The bottle of nail polish can hold 0.35 more ounces
An equation which shows a valid step that can be used to solve the given mathematical equation is ![(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B2x%20-%206%7D%29%5E3%20%3D%20%28-%5Csqrt%5B3%5D%7B2x%20%2B%206%7D%29%5E3)
<h3>What is an equation?</h3>
An equation simply refers to a mathematical expression that can be used to show the relationship existing between two (2) or more numerical quantities.
In this exercise, you're required to show a valid step which can be used to solve the given mathematical equation. Since both equations are having a cube root, the first step is to take the cube of both sides.
Take the cube of both sides, we have:
![\sqrt[3]{2x - 6} + \sqrt[3]{2x + 6} = 0\\\\(\sqrt[3]{2x - 6})^3 + (\sqrt[3]{2x + 6})^3 = 0^3\\\\(\sqrt[3]{2x - 6})^3 = (-\sqrt[3]{2x + 6})^3](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B2x%20-%206%7D%20%2B%20%5Csqrt%5B3%5D%7B2x%20%2B%206%7D%20%3D%200%5C%5C%5C%5C%28%5Csqrt%5B3%5D%7B2x%20-%206%7D%29%5E3%20%2B%20%28%5Csqrt%5B3%5D%7B2x%20%2B%206%7D%29%5E3%20%3D%200%5E3%5C%5C%5C%5C%28%5Csqrt%5B3%5D%7B2x%20-%206%7D%29%5E3%20%3D%20%28-%5Csqrt%5B3%5D%7B2x%20%2B%206%7D%29%5E3)
Read more on equations here: brainly.com/question/13170908
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pls mark as brainlist
Step-by-step explanation:
624 divided by 8 = 78
Answer:
7kg of potatoes cost 56 R (dollars)
Step-by-step explanation:
First, we have to find the unit price of 1kg of potatoes. To do this we divide <em>24 by 3</em>. That's <em>8</em>. Each kg of potato costs 8 dollars.
Now, all we have to do is multiply <u><em>8 by 7</em></u>.
8 is the unit rate/kg and 7kg is the amount they are asking.
<u><em>8x7=56</em></u>
7kg of potatoes cost 56R
