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3 years ago

What is a simplified expression for the perimeter of the polygon?

Mathematics

2 answers:

serious [3.7K]3 years ago

7 0

Answer:

D. 5x^2 + 2y^2 + 12x + 5y

Step-by-step explanation:

6x + 2y + y^2 + 6x + 2y + y^2 + 4x^2 + x^2 + y

6x + 6x = 12x

12x + 2y + y^2 + 2y + y^2 + 4x^2 + x^2 + y

2y + 2y + y = 5y

12x + 5y + y^2 + y^2 + 4x^2 + x^2

y^2 + y^2 = 2y^2

2y^2 + 4x^2 + x^2 + 12x + 5y

4x^2 + x^2 = 5x^2

2y^2 + 5x^2 + 12x + 5y

5x^2 + 2y^2 + 12x + 5y

alexandr1967 [171]3 years ago

3 0

Answer:

$5 {x}^{2} + 2 {y}^{2} + 12x + 5y$

Step-by-step explanation:

Add all of the sides of the polygon:

$6x + 2y + {y}^{2} + 6x + 2y + {y}^{2} + 4 {x}^{2} + {x}^{2} + y$

Combine like terms.

$12x + 5y + 2 {y}^{2} + 5 {x}^{2}$

$5 {x}^{2} + 2 {y}^{2} + 12x + 5y$

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Read 2 more answers

Square lMNO is shown in the diagram below what are the coordinates of the midpoint of a diagonal LN

sashaice [31]

Answer:

The coordinates of the midpoint of LN are $(-2\frac{1}{2},4\frac{1}{2})$

answer (4)

Step-by-step explanation:

* Lets explain how to find the midpoint of a line

- The coordinates of the midpoint of a line whose endpoints are (x1 , y1)

and (x2 , y2) are $x=\frac{x_{1}+x_{2}}{2},y=\frac{y_{1}+y_{2}}{2}$

∵ LMNO is a square

∵ The coordinates of point L are (-6 , 1)

∵ The coordinates of point N are (1 , 8)

- Let the coordinates of point L are (x1 , y1) , the coordinates of point

N are (x2 , y2) and the coordinates of the midpoint of LN are (x , y)

∴ x1 = -6 , x2 = 1 and y1 = 1 , y2 = 8

- Use the rule of the midpoint above to find the midpoint (x , y)

∵ $x=\frac{-6+1}{2}=\frac{-5}{2}=-2\frac{1}{2}$

∵ $y=\frac{1+8}{2}=\frac{9}{4}=4\frac{1}{2}$

∴ The coordinates of the midpoint are $(-2\frac{1}{2},4\frac{1}{2})$

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2 years ago

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Answer:

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Step-by-step explanation:

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divide 2 on each

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