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lorasvet [3.4K]
3 years ago
14

G(-j)=-j-3 find g( - j). Simplify your answer.

Mathematics
1 answer:
postnew [5]3 years ago
3 0

Answer:

-4

Step-by-step explanation

g x negative Jay if you don't have a number in front of the G or J than the numbers going to be one so then you will multiply 1 by -1 which will equal negative one and then negative one minus three what to equal -4

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What is the cosine of angle F <br><br>A. 4/5<br>B. 3/4<br>C. 5/4<br>D. 3/5​
saveliy_v [14]

Answer: option D

Step-by-step explanation:

Remember the cosine identity:

cos\alpha=\frac{adjacent}{hypotenuse}

Given the right triangle DFE shown in the image, you can identify that the adjacent side and the hypotenuse for the angle F of this triangle are:

adjacent=15\\hypotenuse=25

Now you can substitute values into  cos\alpha=\frac{adjacent}{hypotenuse} and then reduce the fraction.

THerefore you get:cos(F)=\frac{15}{25}\\\\cos(F)=\frac{3}{5}

6 0
3 years ago
Read 2 more answers
Suppose that the weight (in pounds) of an airplane is a linear function of the total amount of fuel (in gallons) in its tahk. Wh
kvasek [131]

Answer:

2002 pounds

Explanation:

To know the weight of the plane, we need to find an equation that relates the amount of fuel to the weight.

This equation can be founded using the following

y-y_1=m(x-x_1)

Where m is the slope, x1 is the number of gallons and y1 is the respective weight. So, replacing m = 6.0, x1 = 51 gallons and y1 = 2206 pounds, we get:

y-2206=6(x-51)

Now, we can solve for y

\begin{gathered} y-2206=6(x)-6(51) \\ y-2206=6x-306 \\ y=6x-306+2206 \\ y=6x+1900 \end{gathered}

Then, we can calculate the weight of an airplane with 17 gallons of fuel replacing x = 17 on the equation above

y = 6x + 1900

y = 6(17) + 1900

y = 102 + 1900

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Therefore, the answer is 2002 pounds

5 0
1 year ago
What is (5-sqrt of 2)(3-sqrt of 2)
AVprozaik [17]
Then the answer is 17 minus 8 times the square root of 2, or 5.68629
5 0
3 years ago
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iren2701 [21]

Answer:

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Step-by-step explanation:

We can use the geometric mean theorem:

The altitude on the hypotenuse is the geometric mean of the two segments it creates.

In your triangle, the altitude is the radius CM and the segments are AC and BC.

CM = \sqrt{AC \times BC} = \sqrt{ 9 \times 4} = \sqrt{36} = \mathbf{6}\\\text{The radius of the circle M is $\large \boxed{\mathbf{6}}$}

5 0
3 years ago
Which graph is the result of reflecting f(x) = (8)* across the y-axis and then across the x-axis? O 8- 6- 8 7 ​
marta [7]

I assume you meant f(x)=8^x.

Reflecting across the x-axis would give y=-8^x.

Reflecting across the y-axis would give y=8^{-x}.

8 0
2 years ago
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