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OleMash [197]
3 years ago
13

The first six nonzero multiples of 3

Mathematics
2 answers:
skad [1K]3 years ago
8 0
The first six multiples are 3, 6, 9, 12, 15, 18
True [87]3 years ago
6 0
They are 6;9;12;15;18 and 21
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What is the ratio of the circumferences for two circles with areas 6π m2 and 150π m2?
hichkok12 [17]
\bigg( \dfrac{Length_1}{Length_2} \bigg)^2 = \bigg(  \dfrac{Area_1}{Area_2}\bigg)


\bigg( \dfrac{Length_1}{Length_2} \bigg)^2 = \bigg(  \dfrac{6 \pi }{150 \pi }\bigg)


\bigg( \dfrac{Length_1}{Length_2} \bigg)^2 = \bigg(  \dfrac{1 }{25}\bigg)


\dfrac{Length_1}{Length_2} =   \sqrt{ \dfrac{1}{25} } 


\dfrac{Length_1}{Length_2} =   \dfrac{1}{5}

-------------------------------------------------------------
Answer: The ratio of the two circles = 1 :5 
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8 0
3 years ago
Find the midpoint of points A(10,-7) and B(6, 1) graphically.
sashaice [31]

Answer:

(8,-3)

Step-by-step explanation:

<u>Midpoint Formula: </u> (\frac{x^{1}+x^{2}  }{2}, \frac{y^{1} +y^{2} }{{2} }   )

Plug in your numbers from the coordinates:

(10+6/2, -7+1/2)

(16/2, -6/2)

(8,-3)

4 0
2 years ago
A train traveled a distance of 1 mile, or 5,280 feet, while climbing a hill at an angle of 5°.
Finger [1]
You can draw a right triangle where>

1) the distance traveled, i.e. 5280, is the hypotenuse

2) the opposite-leg is the vertical height that you need to calculate

3) the angle is 5°.

Therefore you can use the trigonometric ratio sine, which is:

sin(angle) = opposite-leg / hypotenuse = vertical height / distance traveled

= vertical height = distance traveled * sin (angle)

=> vertical height = 5,280 ft * sin(5°) = 460,18 ft

Answer: 460,18 ft
7 0
4 years ago
I really really need help on this question what is the answer for this ( how much would it cost to mail a letter that weighs 2.7
prohojiy [21]

It costs $.50 to mail a letter of that size.

All letters that are under 3.5 oz take only one stamp to ship. Since 2.7 is less, it would cost only $.50

5 0
3 years ago
Consider the points.
miskamm [114]

Answer:

6 units

Step-by-step explanation:

Use the distance formula, \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}.

Plug the x and y values from the given points into the distance formula:

\sqrt{([-4]-2)^{2}+(5-5)^{2}}.

Solve the square root:

\sqrt{36} = \sqrt{6^{2}} = 6

3 0
3 years ago
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