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MrRa [10]
3 years ago
12

Which points in the scatter plot are outliers?

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
3 0
An outlier<span> is an observation that lies an abnormal distance from other values in a random sample from a population. In a sense, this definition leaves it up to the analyst (or a consensus process) to decide what will be considered abnormal. Before abnormal observations can be singled out, it is necessary to characterize normal observations.  


Basically the ones that are far away from the others.

Thus, the outliers for this graph are K and F

</span>
Aleonysh [2.5K]3 years ago
3 0
The outliers would be values k and f
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What is 5(n-1)=2(n-4)-6
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Answer:

Step-by-step explanation

6n - 6 = 2 (n+1)

Simplify 2 (n+1)

6n - 6= 2n +2

Move all terms related to n to the left side of the equation

4n -6 =2

Move all terms not related to n to the right side of the equation

4n =8

Divide each term by 4 then simplify

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5 0
3 years ago
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This is a System Of Equations and I'd like it to get solved by the Elimination or Substitution Method.x+2y=83x+5y=8
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Answer:

x=133 y=-25

Step-by-step explanation:

I'll do both ways for you. So let's start with Substitution:

With the sub method, you have to set both equations equal to each other by setting them equal to the same variable. Since there is no coefficient in front of both x's in both equations, that variable will be easiest to solve for.

x + 2y = 83    &    x + 5y = 8

Solve for x.

x = 83 - 2y     &    x = 8 - 5y

Once you have solved for x, set each equation equal to one another and solve for y now.

83 - 2y = 8 - 5y

Isolate all variables to one side:

83 = 8 - 3y

Now subtract the 8 to fully isolate the y variable:

75 = -3y

Divide by -3:

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x - 50 = 83

x = 133

Now for the Elimination method. For this method you need to get rid of a variable by either subtracting/adding each equation together. Again, since you can subtract and x from both equations, you will be left with only the y variable to solve:

Put each equation on top of one another and subtract:

  x + 2y = 83

- (x + 5y = 8)

The x's will cancel out:

(x - x) + (2y - 5y) = (83 - 8)

Simplify:

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Solve for y

y = -25

Then, plug y = -25 into one of the original equations:

x + 5(-25) = 8

Solve for x:

x - 125 = 8

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Hope this helps!

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Answer:

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