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Lady bird [3.3K]
3 years ago
10

Find the product. Write the product in simplest form. 8 X 5/7

Mathematics
1 answer:
goblinko [34]3 years ago
6 0

Answer:

Simplify above fraction

56

6

Common divisor of (56, 6) is 2

Divide both numerator & denominator by gcd value 2

56

6

=

56

÷

2

6

÷

2

=

28

3

8

3

×

7

2

=

28

3

Step-by-step explanation:

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How to solve? Would you divide by 4? 4 representing the four corners
charle [14.2K]

Answer:

paper left = 168.56 units²

Step-by-step explanation:

first, figure the area of the square:

area of square = 28x28 = 784 units²

second, figure the area of the circle:

radius = 1/2of 28 = 14

area of circle = Pi x Radius² = (3.14)(14)² = 615.44 units²

subtract area of circle from area of square:

784 - 615.44 = 168.56 units²

3 0
3 years ago
2.413km to M <br> convert each measurement to the unit indicated
Leni [432]

Answer: 2431

Step-by-step explanation: i think this is right use a conversion calculater if i am wrong

5 0
3 years ago
Read 2 more answers
Explain the phrase conservation of energy and provide an example.
liubo4ka [24]

Answer:

Conservation of energy, principle of physics according to which the energy of interacting bodies or particles in a closed system remains constant. ... For example, when a pendulum swings upward, kinetic energy is converted to potential energy.

Step-by-step explanation:

3 0
3 years ago
A traffic light at a certain intersection is green 50% of the time, yellow 10% of the time, and red 40% of the time. A car appro
kati45 [8]

Answer:

6.4\times 10^{-5} = 0.000064 = 0.0064\%.

Step-by-step explanation:

Probability that the car encounters a green light on the first day: 50 \% = 0.5.

To meet the question's conditions, the car needs to encounter another green light on the second day. Given that the colors of the light on each day are "independent," the chance that there's a green light followed by another green light will be

(0.5) \times 0.5 = 0.25.

  • Condition is met on the first two days and green light on the third day: (0.5 \times 0.5) \times 0.5 = 0.125.
  • Condition is met on the first three days and green light on the fourth day:   (0.5 \times 0.5 \times 0.5) \times 0.5.

To meet the condition on the fifth day, there needs to be a yellow light. The probability that the condition is met on the first four days and on the fifth day will be (0.5 \times 0.5 \times 0.5 \times 0.5) \times 0.1 = 0.5^{4} \times 0.1.

To meet the condition on the sixth day, all prior days should meet the conditions. Besides, there needs to be a red light on the sixth day. (0.5^{4} \times 0.1) \times 0.4

  • Seventh day: (0.5^{4} \times 0.1 \times 0.4 ) \times 0.4
  • Eighth day: (0.5^{4} \times 0.1 \times 0.4^2 ) \times 0.4
  • Ninth day: (0.5^{4} \times 0.1 \times 0.4^3 ) \times 0.4
  • Tenth day: (0.5^{4} \times 0.1 \times 0.4^4 ) \times 0.4 = 0.5^{4} \times 0.1 \times 0.4^{5}

The question asks that the condition be met on all ten days. As a result, the probability of meeting the condition will be equal to the probability on the tenth day: 0.5^{4} \times 0.1 \times 0.4^{5} = 6.4\times 10^{-5} = 0.000064 = 0.0064\%.

6 0
3 years ago
Read 2 more answers
The life times of light bulbs produced by a particular manufacturer have a mean of 1,200 hours and a standard deviation of 400 h
Nezavi [6.7K]

Answer:

a. 1200hours

b.  σ² = 400² =160000hour

c. standard error = 133.33

d. for 9 lightbulb it is likely that 9*0.146 = 1.31 bulbs will have lives of fewer than 1,050 hours?

Step-by-step explanation:

mean of 1,200 hours

σ, a standard deviation of 400 hours.

Sample size, N =  nine bulbs,

a) mean of the sample mean lifetime: is given as 1,200 hours

b) variance of the sample mean is the square of the  σ, a standard deviation of 400 hours.

σ² = 400² =160000hours

c) What is the standard error of the sample mean?

The standard deviation of a sampling distribution of mean values is called the standard error of the means,

standard error of the means,  σx = σ √N

The formula for the standard error of the means is true for all values infinite number of sample, N.

σx = σ √N

     =400  √9 = 400/3 =133.3333

d) the probability that, on average, those nine lightbulbs have lives of fewer than 1,050 hours

The area under part of a normal probability curve is  directly proportional to probability and the value is calculated as

z = ( x₁−x) /σ

where z = propability of normal curve

x₁ = variate mean = 1050hours

x = mean of 1200hours

σ = standard deviation = 400

applying the formula,

z= (1050-1200)/400

z = 150/400 =0.375

Using a table of partial areas beneath the standardized normal curve (see Table of normal curve, a z-value of 0.375 corresponds to an area of 0.1460 between the mean value.

Thus the probability of a lightbulbs having lives of fewer than 1,050 hours is 0.1460.

for 9 lightbulb it is likely that 9*0.146 i.e. 1.31 bulbs will have lives of fewer than 1,050 hours?  

8 0
3 years ago
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