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xz_007 [3.2K]
3 years ago
13

Find the area of a parallelogram with the given vertices. P(-2, -5), Q(9, -5), R(1, 5), S(12, 5)

Mathematics
1 answer:
valentina_108 [34]3 years ago
4 0

Answer:

The area of the parallelogram is 55 square unit.

Step-by-step explanation:

The area of a parallelogram is

A=\frac{1}{2}\times base\times height

It is given that the vertices of the parallelogram are  P(-2, -5), Q(9, -5), R(1, 5), S(12, 5).

Plot these points on a coordinate plane, and draw a perpendicular on PQ from the point R.

From the graph is clear that length of PQ is 11 and the height of the parallelogram is 10. So, the area of a parallelogram is

A=\frac{1}{2}\times 11\times 10

A=55

Therefore the area of the parallelogram is 55 square unit.

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Answer:

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Step-by-step explanation:

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Amount taken on loan = 4300

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6 1/3 (denominator is 3): 3 6 9 12 15

Look and see which is the first multiple that all three denominators have. Circle them if it helps you. In this case, it's 12.

So now we have to multiply the denominators by whatever number it takes to reach 12, and multiply by the same number to the numerator:

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Thus, Peter makes a total of 13 1/2 cups.

Hope this made sense! tell me if anything is confusing/incorrect :))
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