Question

Find the area of a parallelogram with the given vertices. P(-2, -5), Q(9, -5), R(1, 5), S(12, 5)

Answer 1

Answer:

The area of the parallelogram is 55 square unit.

Step-by-step explanation:

The area of a parallelogram is

$A=\frac{1}{2}\times base\times height$

It is given that the vertices of the parallelogram are  P(-2, -5), Q(9, -5), R(1, 5), S(12, 5).

Plot these points on a coordinate plane, and draw a perpendicular on PQ from the point R.

From the graph is clear that length of PQ is 11 and the height of the parallelogram is 10. So, the area of a parallelogram is

$A=\frac{1}{2}\times 11\times 10$

$A=55$

Therefore the area of the parallelogram is 55 square unit.