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Bogdan [553]
3 years ago
8

Which of the following values have 3 significant figures? Check all that apply.

Mathematics
1 answer:
iogann1982 [59]3 years ago
4 0

Answer:D

Step-by-step explanation:

You might be interested in
For each sentence, drag a word that will make the statement true.
olchik [2.2K]

Answer:

Equilateral triangles are always acute triangles.

Scalene triangles are sometimes acute triangles.

Right triangles are never acute triangles.

Obtuse triangles are sometimes isosceles triangles.

Step-by-step explanation:

Equilateral triangles are always acute because each angle is 60⁰.

Scalene triangles have sides that are different lengths. They can be right, obtuse, or acute.

A right triangle is never acute because it has a 90⁰ angle. Acute means all angles are less than 90⁰.

An obtuse triangle can be either scalene or isosceles. It always has one angle greater than 90⁰ (obtuse).

4 0
3 years ago
Which statements are true for the functions g(x) = x2 and h(x) = –x2 ?
svp [43]

Answer:

g(x) > h(x) for x = -1.

For positive values of x, g(x) > h(x).

For negative values of x, g(x) > h(x).

6 0
2 years ago
The graph of part of linear function p is shown on the grid.
Rufina [12.5K]

Answer:

A

Step-by-step explanation:

The domain of a function is the span of x-values covered by the graph.

From the graph, we can see that it stretches from x=-7 to x=2.

However, note that at x=-7, the dot is closed (shaded in). In other words, x=-7 <em>is</em> in our domain.

On the other hand, at x=2, the dot is not shaded. So, x=2 is <em>not</em> included in our domain.

Therefore, our domain all are numbers between -7 and 2 including -7 (and not including 2).

As a compound inequality, this is:

-7\leq x

So, our answer is A.

Also note that we use x instead of p(x) because the domain relates to the x-variable. If we were to instead find the range, then we would use p(x).

4 0
3 years ago
Read 2 more answers
Plz answer BRAINLIEST Choose the statement that is true of both triangles.
saw5 [17]

Answer:

b

Step-by-step explanation:

gjhghjghj

8 0
3 years ago
A signalized intersection has a cycle length of 60 seconds and an effective red time of 25 seconds. The effective green time is
alexandr402 [8]

Answer:

effective green time = 35 seconds

Step-by-step explanation:

given data

cycle length = 60 seconds

effective red time = 25 seconds

solution

we get here  effective green time that is express as

effective green time = cycle length  - effective red time   ...........................1

put here value and we will get

effective green time = 60 seconds - 25 seconds

effective green time = 35 seconds

3 0
3 years ago
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