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Maurinko [17]
3 years ago
14

A salesperson had the following sales: $15.50, $18.98, s16.8, $14, $18.50, and $22. What was the average sale?

Mathematics
1 answer:
Jlenok [28]3 years ago
5 0

Answer:

$ 17.63

Step-by-step explanation:

Given,

The sales of the salesperson are,

$15.50, $18.98, $16.8, $14, $18.50, and $22,

Sum of sales = 15.50 + 18.98 + 16.8 + 14  + 18.50 + 22 = 105.78

Also, the number of sales = 6,

Thus, the average sale = \frac{\text{Sum of sales}}{\text{Number of sales}}

=\frac{105.78}{6}

= $ 17.63

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Step-by-step explanation:

2 triangles makes a square

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times how many triangles to how much grams each triangle weights

3 0
4 years ago
5^(-x)+7=2x+4 This was on plato
Setler79 [48]

Answer:

Below

I hope its not too complicated

x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

Step-by-step explanation:

5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}

Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}

\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x

\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}

3 0
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3 0
3 years ago
Which statement correctly describes the relationship between the graph of f(x) and g(x)=f(x+2) ?
Ahat [919]

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7 0
4 years ago
Read 2 more answers
If -2 is added to a number and the sum is doubled, the result is -15 less than the number.
VMariaS [17]

The required number is 19 given that -2 is added to a number, the sum is doubled and the result is -15 less than the number. This can be obtained by assuming the number as x, converting the given conditions to algebraic expression, forming algebraic equation and solving for x.

<h3>Find the required number:</h3>

Here in the question it is given that,

  • -2 is added to a number
  • The sum is doubled
  • The result is -15 less than the number

We have to find the required number.

Let the required number be x.

⇒ -2 is added to the number ⇒ -2 + x

⇒ the sum is doubled ⇒ 2(-2 + x)

⇒ the result is -15 less than the number ⇒ 2(-2 + x) = x -(-15)

2(-2 + x) = x + 15

⇒ - 4 + 2x = x + 15

⇒ x = 19

Hence the required number is 19 given that -2 is added to a number, the sum is doubled and the result is -15 less than the number.

Learn more about algebraic expression and equation here:

brainly.com/question/953809

#SPJ9

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2 years ago
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