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trapecia [35]
3 years ago
7

An exam was given to a group of freshman and sophomore students. The results are below: Freshman: 106 got A’s, 130 got B’s, and

149 got C’s. Sophomore: 192 got A’s, 118 got B’s, and 168 got C’s. If one student is chosen at random from those who took the exam, find the probability that: a) the student was a sophomore. round to 4 decimal places as needed.
Mathematics
1 answer:
masha68 [24]3 years ago
3 0

Answer:         0.140

Step-by-step explanation:

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Nuetrik [128]

Answer:

At any given moment, the red ant's coordinates may be written as (a, a) where a > 0. The  red ant's distance from the anthill is a\sqrt{2} . The black ant's coordinates may be written  as (-a, -a) and the black ant's distance from the anthill is a\sqrt{2}  . This shows that at  any given moment, both ants are  a\sqrt{2} units from the anthill.

Step-by-step explanation:

Given:

red ant's coordinates written as (a,a)

black ant's coordinates are written  as (-a, -a)

To find:

The distance of red and black ants from anthill

Solution:

Compute the distance of red ant from the anthill using distance formula

d (red ant) = \sqrt{(a-0)^{2}+ (a-0)^{2}}

                 = \sqrt{a^{2} + a^{2} }

                 = \sqrt{2a^{2} }

                 = a\sqrt{2}

So distance of red ant from anthill is a\sqrt{2}

Compute the distance of black ant from the anthill using distance formula

d (black ant) = \sqrt{(-a-0)^{2}+ (-a-0)^{2}}

                    = \sqrt{(-a)^{2} + (-a)^{2} }

                    = \sqrt{a^{2} + a^{2} }

                 = \sqrt{2a^{2} }

                 = a\sqrt{2}

So distance of black ant from anthill is a\sqrt{2}

Hence both ants are a\sqrt{2}   units from the anthill.

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