In a study of the accuracy of fast food drive-through orders, one restaurant had 32 orders that were not accurate among 367 orders observed. Use a 0.05 significance level to test the claim that the rate of inaccurate orders is equal to 10%. Does the accuracy rate appear to be acceptable?

Answer:

The decision rule is

Fail to reject the null hypothesis

The conclusion is

There is sufficient evidence to show that the rate of inaccurate orders is equal to 10%

Step-by-step explanation:

Generally from the question we are told that

The sample size is n = 367

The number of orders that were not accurate is $k = 32$

The population proportion for rate of inaccurate orders is p = 0.10

The null hypothesis is $H_o : p = 0.10$

The alternative hypothesis is $H_a : p \ne 0.10$

Generally the sample proportion is mathematically represented as

$\^ p = \frac{k}{n}$

=> $\^ p = \frac{32}{367}$

=> $\^ p = 0.0872$

Generally the test statistics is mathematically represented as

$z= \frac{ \^ p - p }{ \sqrt{ \frac{ p(1 - p)}{ n} } }$

=> $z= \frac{ 0.0872 - 0.10 }{ \sqrt{ \frac{ 0.10 (1 - 0.10 )}{367} } }$

=> $z= -0.8174$

From the z table the area under the normal curve to the left corresponding to -0.8174 is

$P(z < -0.8173 ) = 0.20688$

Generally the p-value is mathematically represented as

$p- value = 2 * 0.20688$

=> $p- value = 0.4138$

From the value obtained we see that $p-value > \alpha$ hence

The decision rule is

Fail to reject the null hypothesis

The conclusion is

There is sufficient evidence to show that the rate of inaccurate orders is equal to 10%

4 0

2 years ago

How tall is the flagpole?

Fudgin [204]

51 ft is the answer

Explanation

The hight of the man divided by the hight of school ( which is unknown )

Equal

The length of the shadow of the man divided by the shadow of the school

Cross multiplication and find the value of unknown x which is 51... and ya

4 0

2 years ago

Surveys indicate that two-thirds of all voters in Ward 5 plan on choosing Spike Jones for commissioner. If there are 500 voters

olya-2409 [2.1K]

Answer:

333 people of ward 5 are going to be voting for Spike Jones.

Solution:

We have been given that two-thirds of all voters in Ward 5 plan on choosing Spike Jones for commissioner.

There are 500 voters in Ward 5.

Since 2/3 of all voters in Ward 5 are voting for Spike Jones the remaining 1/3 will not be voting for him.

To find out how many people in ward 5 are exactly voting for Spike Jones. We need to calculate how much is two thirds of 500 is.

This is done as follows:

$\begin{array}{l}{\frac{2}{3} \times 500} \\\\ {=\frac{1000}{3}} \\\\ {=333.334}\end{array}$

Since people cannot be denoted in decimal points we have to round it off to a whole number. That’s is 333.

Therefore 333 people of ward 5 are going to be voting for Spike Jones.

4 0

2 years ago