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Alinara [238K]
3 years ago
11

ABCD=STQR. What is the measurement of CD?

Mathematics
2 answers:
vaieri [72.5K]3 years ago
7 0

Answer:

CD= 21 in

Step-by-step explanation:

CD is the same length as QR

QR= 21

USPshnik [31]3 years ago
6 0

Step-by-step explanation:

\because \: ABCD=STQR...(Given) \\  \\  \therefore \: CD = QR \\  \\  \because \: QR = 21 \: in \\  \\  \huge \red{ \boxed{\therefore \: CD =21 \: in }}

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x+5y=12

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A mountain climber needs to descend 3,435 feet. He wants to do it in 4 equal descents. How far should he travel in each descent?
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3 years ago
The radius of the cone is 1.25 inches, and its height is 2.75 inches. If the diameter of the bubble gum ball is 0.5 inches, what
nasty-shy [4]
<h2>Explanation:</h2><h2></h2>

The volume of a cone can be found as:

V=\frac{1}{3}\pi r^2 h \\ \\ \\ Where: \\ \\ V:Volume \\ \\ r:radius \ of \ base \\ \\ h:height

Given the radius and height, we can find the volume of the cone:

V=\frac{1}{3}\pi r^2 h \\ \\ V=\frac{1}{3}\pi (1.25)^2(2.75) \\ \\ V=\frac{1}{3}\pi(1.5625)(2.75) \\ \\ V\approx 4.5in^3

The volume of a sphere is:

V=\frac{4}{3}\pi r^3 \\ \\ \text{Each gum ball has a diameter of 0.5in, so the radius is:} \\ \\ r=\frac{0.5}{2}=0.25in

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V=\frac{4}{3}\pi r^3 \\ \\ V=\frac{4}{3}\pi (0.25)^3 \\ \\ V=0.065in^3

Therefore, the he closest approximation of the volume of the cone that can be filled with flavored ice is:

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3 0
3 years ago
A cylinder closed tin of radius r cm is made from 600cm2 tin sheet of metal.
Zarrin [17]

Answer:

Note:  The expression "h =300- pi r /pi r" would equate to 299, as written.  I find h = (300 - πr^{2} )/πr to be the equation for height.

Step-by-step explanation:

The total surface area of a sylinder is 2πr(h+r) where h is the height and r is the radius.  That consists of top and bottom disks, each with an area of πr^{2}, for a total of 2πr^{2}.  The side is a  continous sheet that has an area of 2πrh, where h is the height.  2πr is the circumference of the can, so the surface area of the side is 2πrh.

The total surace area of a closed cylinder is therefore 2πr^{2} + 2πrh.

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πr^{2} + πrh = 300

πrh = 300 - πr^{2}

h = (300 - πr^{2} )/πr

7 0
2 years ago
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