Part A: The final volume of the new solution is 150 mL.
Part B: The concentration of the new solution is 0.125 M.
<h3>
What is the volume?</h3>
The volume of liquid is defined as the amount of liquid in a three-dimensional container. Volume is the quantity of three-dimensional space occupied by a liquid.
Given that the molarity of NaCl solution is 0.150 M, the volume of NaCl solution is 125 mL, the volume of water added is 25 mL.
Part A:
The final volume of the new concentrated solution is calculated as given below.
![V = 125 + 25](https://tex.z-dn.net/?f=V%20%3D%20125%20%20%2B%2025)
![V = 150 \;\rm mL](https://tex.z-dn.net/?f=V%20%3D%20150%20%5C%3B%5Crm%20mL)
The final volume of the new solution is 150 mL.
Part B:
The mole of the NaCl solution is calculated using the molarity formula.
Molarity of NaCl solution = 0.150 M
Volume of NaCl solution = 125mL or 0.125 L
Molarity = Mole of NaCl solution / Volume of the NaCl solution
![0.150 = \dfrac {Moles}{Volume}](https://tex.z-dn.net/?f=0.150%20%3D%20%5Cdfrac%20%7BMoles%7D%7BVolume%7D)
![0,150 = \dfrac {Moles}{0.125}](https://tex.z-dn.net/?f=0%2C150%20%3D%20%5Cdfrac%20%7BMoles%7D%7B0.125%7D)
![Moles \;= 0.01875](https://tex.z-dn.net/?f=Moles%20%5C%3B%3D%200.01875)
The moles of NaCl solution is 0.01875 mole which remains same when water is added. Thus, the molarity of the new concentration can be calculated as given below.
Molarity = Moles of NaCl / Volume of new solution
Molarity = ![\dfrac {0.01875}{0.150}](https://tex.z-dn.net/?f=%5Cdfrac%20%7B0.01875%7D%7B0.150%7D)
Molarity = 0.125 M
Hence we can conclude that the concentration of the new solution is 0.125 M.
To know more about the volume, follow the link given below.
brainly.com/question/24650225.