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Lelechka [254]
3 years ago
14

given the functions f(x)=4x^2-1, g(x)=x^2-8x+5, and h(x)=-3x^2-12x +1, rank them from least to greatest based on their axis of s

ymmetry
Mathematics
1 answer:
Lesechka [4]3 years ago
7 0
The formula for axis of symmetry is -b/2a.

For f(x):
0/2(4)
0/8
Axis of symmetry= 0

For g(x)
-(-8)/2(1)
8/2
Axis of symmetry= 4

For h(x)
-(-12)/2(-3)
12/-6
Axis of symmetry= -2

Order from least to greatest: -2, 0, 4

Final answer: h(x), f(x), g(x)
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6 x 7 = 42

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HELP MEE!!!|||||||||Find the volume of a cylinder with a diameter of 6 inches and a height that is three times the radius. Use 3
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Answer: There are several information's of immense importance already given in the question. Let us write them down first.

Diameter of the cylinder = 6 inches

Then

Radius of the cylinder = 3 inches.

Height of the cylinder = 3 * radius

                                  = 3 * 3

                                  = 9 inches

Volume of the cylinder = (pi) * (Radius)^2 * Height

                                   = 3.14 * (3)^2 * 9

                                   = 3.14 * 9 * 9

                                   = 254.34 cubic inches

7 0
3 years ago
A sandwich shop serves 4 ounces of meat and 3 ounces of cheese on each sandwich. After making sandwiches for an hour, the shop o
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Answer:

7 oz, 13 sandwiches, 22.75 oz, and  30.33 oz.

Step-by-step explanation:

4 0
3 years ago
the pitch, or frequency, of a vibrating string varies directly with the square root of the tension. if a string vibrates at a fr
Naily [24]
\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad  variation
\end{array}\\\\
-------------------------------\\\\
\begin{array}{llll}
\stackrel{frequency}{f}\textit{ of a vibrating string varies directly}\\
\qquad \qquad \textit{with the square root of the tension }\stackrel{tension}{t}
\end{array}

\bf f=k\sqrt{t}\quad \textit{we also know that }
\begin{cases}
f=300\\
t=8
\end{cases}\implies 300=k\sqrt{8}
\\\\\\
\cfrac{300}{\sqrt{8}}=k\implies \cfrac{300}{\sqrt{2^2\cdot 2}}=k\implies \cfrac{300}{2\sqrt{2}}=k\implies \cfrac{150}{\sqrt{2}}=k
\\\\\\
\textit{and we can \underline{rationalize} it to }\cfrac{150\sqrt{2}}{2}\implies 75\sqrt{2}=k

\bf thus\qquad f=\stackrel{k}{75\sqrt{2}}\sqrt{t}\implies \boxed{f=75\sqrt{2t}}\\\\
-------------------------------\\\\
\textit{now, when t = 72, what is \underline{f}?}\qquad f=75\sqrt{2(72)}
5 0
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