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4 years ago

15

PLZ HELP DUE SOON!!!!!!

1 answer:

ANEK [815]4 years ago

3 0

Let's factor the following polynomial to find the roots:
x2-13x + q = 0
Factoring we have:
(x-12.5) * (x + a)
Where,
-12.5 + a = -13
a = -13 + 12.5
a = -0.5
We now look for the coefficient q:
q = -12.5 * a
q = -12.5 * (- 0.5)
q = 6.25
The polynomial will then be:
x2-13x + 6.25 = 0
Its roots are:
x1 = 12.5
x2 = 0.5
Answer:
The other root and the value of the coefficient are:
0.5 and 6.25 (Respectively)

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What is the value of 3 in 6035

Sveta_85 [38]

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So I would say 3's value is tenths.

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4 years ago

If an object is launched at an angle of 28° with an initial velocity of 133 ft./s from a height of 6 feet how many seconds will

Tema [17]

Answer:

Hence after 3.98 sec i.e 4 sec Object will hit the ground .

Step-by-step explanation:

Given:

Height= 6 feet

Angle =28 degrees.

V=133 ft/sec

To Find:

Time in seconds after which it will hit the ground?

Solution:

<em>This problem is related to projectile motion for objec</em>t

First calculate the Range for object and it is given by ,

$R=v^2Sin$ (2Ф)/ $g$

Here R= range g= acceleration due to gravity =9.8 m/sec^2

1m =3.2 feet

So 9.8 m, equals to 9.8 *3.2=31.36 ft

So g=31.36 ft/sec^2. and 2Ф=2(28)=56

$R=133^2*Sin(56)/31.36$

$R=14664.84/31.36$

$R=467.62$ fts

Now using Formula for time and range as

$R=VxT$

Vx is horizontal velocity

$Vx=V*cos$ Ф

$Vx=133*cos$ (28)

$Vx=117.43$ ft/sec

So above equation becomes as ,

$467.62=117.43*T$

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4 0

4 years ago

PLEASE HELP ME THIS IS DUE IN TWO HOURS! :(

Damm [24]

Answer:

2.0 x $10^{1}$

Step-by-step explanation:

1. length = 3.2 x $10^{5}$ m

width = 1.6 x $10^{4}$ m

Area of a rectangle = length x width

= (3.2 x $10^{5}$ ) x (1.6 x $10^{4}$ )

= 5.12 x $10^{9}$ $m^{2}$

2. length = 1.28 x $10^{7}$ m

width = 8 x $10^{3}$ m

Area of a rectangle = length x width

= (1.28 x $10^{7}$ ) x (8 x $10^{3}$ )

= 1.024 x $10^{11}$ $m^{2}$

$\frac{Area of rectangle 2}{Area of rectangle 1}$ = $\frac{1.024*10^{11} }{5.12*10^{9} }$

= 20

= 2.0 x $10^{1}$

Thus,

The area of rectangle 2 is 2.0 x $10^{1}$ times greater than the area of rectangle 1.

5 0

3 years ago