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Zolol [24]
3 years ago
8

Let a be a non-zero rational number and b be an irrational number. Is a x b rational or irrational?

Mathematics
1 answer:
pentagon [3]3 years ago
8 0

Answer:

rational

Step-by-step explanation:

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It’s B correct answer
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write a word problem that can be solved using multiplication of two-digit numbers.Solve your word problem explain the solution.
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____ was planning a birthday party. He/she is planning on inviting 14 people to the party. Each person will be given a goodie-bag at the end of the party. ____ decided that he/she will put 19 gummy worms into each bag. how many gummy worms will ____ need?

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2 years ago
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8th Grade Math Equation. Please help! I accept any type of help!
muminat

Hello from MrBillDoesMath!

Answer:

Positive x-intercept =  + sqrt(3)

Negative x-intercept = - sqrt(3)


Discussion:

Generally, the x-intercept of a function g(x) occurs where g(x) = 0. In our case this is

g(x) = 0   =>

3x^2 - 9 = 0     =>                         (add 9 to both sides of the equation)

3 x^2      = 9    =>                         (divide both sides by 3)

x^2 = 9/3 = 3  =>

x = +\- sqrt (3)

Positive x-intercept =  + sqrt(3)

Negative x-intercept = - sqrt(3)



Thank you,

MrB

5 0
3 years ago
2 If m please help me
Nadusha1986 [10]

Answer:

x = 18

m∠HCB = 36

Step-by-step explanation:

The measure of angle FBC is 8x and the measure of angle HCB is 2x. If you add the measures of both angles it will equal to 180 degrees. This can be represented in an equation:

8x + 2x = 180

10x = 180

Divide both sides of the equation by 10 to isolate the x:

10x/10 = 180/10

x = 18

Now that we know the value of x, we can find the measure of angle HCB:

2x

2(18)

36

The measure of angle HCB is 36.

I hope this helps :)

8 0
2 years ago
(15 pts) 4. Find the solution of the following initial value problem: y"-10y'+25y = 0 with y(0) = 3 and y'(0) = 13
jolli1 [7]

Answer:

y(x)=3e^{5x}-2xe^{5x}

Step-by-step explanation:

The given differential equation is y''-10y'+25y=0

The characteristics equation is given by

r^2-10r+25=0

Finding the values of r

r^2-5r-5r+25=0\\\\r(r-5)-5(r-5)=0\\\\(r-5)(r-5)=0\\\\r_{1,2}=5

We got a repeated roots. Hence, the solution of the differential equation is given by

y(x)=c_1e^{5x}+c_2xe^{5x}...(i)

On differentiating, we get

y'(x)=5c_1e^{5x}+5c_2xe^{5x}+c_2e^{5x}...(ii)

Apply the initial condition y (0)= 3 in equation (i)

3=c_1e^{0}+0\\\\c_1=3

Now, apply the initial condition y' (0)= 13 in equation (ii)

13=5(3)e^{0}+0+c_2e^{0}\\\\13=15+c_2\\\\c_2=-2

Therefore, the solution of the differential equation is

y(x)=3e^{5x}-2xe^{5x}

5 0
3 years ago
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