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Solnce55 [7]
3 years ago
11

In the DBE 122 class, there are 350 possible points. These points come from 5 homework sets that are worth 10 points each and 3

exams that are worth 100 points each. A student has received homework scores of 7, 8, 7, 5, and 8 and the first two exam scores are 81 and 80. Assuming that grades are assigned according to the standard scale, where if the grade percentage is 0.9 or higher the student will get an A, and if the grade percentage is between 0.8 and 0.9 the student will get a B, and there are no weights assigned to any of the grades, is it possible for the student to receive an A in the class? What is the minimum score on the third exam that will give an A? What about a B?
Mathematics
1 answer:
Lesechka [4]3 years ago
6 0

Answer:

a) The student cannot receive an A in the class.

b) The student must score 119 in the third exams to make an A.  This is clearly not possible, since he cannot make 119 in a 100-points exam.

c) The student can make a B but he must score at least 84 in the third exam.

Step-by-step explanation:

To make an A, the student must score 315 (350 x 90%) in both home and the three exams.

The student who scored 35 (7 + 8 + 7 + 5 + 8) in the homework and 161 (81 + 80), getting a total of 196, is short by 119 (315 - 196) scores in making an A.

To make a B, the student must score 280 (350 x 80%) or higher but not reaching 315.

B ≥ 280 and < 315.

Since, the student had scored 196, he needs to score 84 and above to make a B in the last exam.

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If tanA= 12/5 and A is not acute, find Sin2A and cos2A.​
hammer [34]

Answer: Sin 2A = 14/13

                Cos 2A =10/13

Step-by-step explanation: First do subtraction 12*12 ., then 5*5 ., the result will be 169  , then route it and got the result 13 , last we need to the value of polygon . We will got the  value of polygon 13 . then we will got the actual value of those two result . Hope you got the point.

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3 years ago
The sum of three numbers is 86 the second number is 9 less than the first the third number is 3 times the first what are the num
Kobotan [32]

Answer:

10, 19 and 57

Step-by-step explanation:

let the first number be a, the second be b and the third be c

a+b+c=86

the second number is 9 less than the first

a=b+9------i

b=a-9

the third number is 3 times the first

c=3a------ii

a=c/3

therefore

b+9=c/3

c=3(b+9)

b+9+b+3(b+9)=86

b+9+b+3b+27=86

collecting like terms

5b=86-(27+9)

5b=86-36

5b=50

therefore

b=10

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a=10+9

a=19

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3 years ago
In two or more complete sentences, describe how you would draw the graph of the solution set for the following inequality. -3m+1
Marat540 [252]

First find the value of m by solving the inequality.

Solving the inequality we get value of m: m>-4

Now, for drawing the graph, a dotted line will be on -4, as values greater than -4 are included in the graph. and all the portion on right side of -4 is included in the graph.

Step-by-step explanation:

We need to draw the graph of the solution set for the following inequality. -3m+18 < 30

First we will solve the inequality and find value of m

-3m+18 < 30

Adding -18 on both sides

-3m+18-18 < 30-18\\-3m

Dividing both sides by -3 and reversing the inequality i.e < is changed into >

\frac{-3m}{-3}-4

So, value of m is: m>-4

So. for drawing the graph, a dotted line will be on -4, as values greater than -4 are included in the graph. and all the portion on right side of -4 is included in the graph.

The graph is shown in figure attached.

Keywords: Solving inequalities

Learn more about Solving inequalities at:

  • brainly.com/question/6703816
  • brainly.com/question/11788572
  • brainly.com/question/4192226

#learnwithBrainly

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3 years ago
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