Answer:
y = -3x + 7
Step-by-step explanation:
Choosing two points from the given table:
Let (x1, y1) = (-3, 16)
(x2, y2) = (-1, 10)
Plug these given values into the slope formula:
m = (y2 - y1)/(x2 - x1)
= (10 - 16) / (-1 - (-3))
= -6 / (-1 + 3)
= -6/2
= -3
Therefore, the slope is -3.
Next, choose one of the points and plug into the <u>point-slope form</u>:
Let's use (-1, 10) as (x1, y1):
y - y1 = m(x - x1)
y - 10 = -3(x - (-1))
y - 10 = -3(x + 1)
y - 10 = -3x - 3
Add 10 on both sides to isolate y:
y - 10 + 10 = -3x - 3 + 10
y = -3x + 7
Answer:
Step-by-step explanation:
13:6
9514 1404 393
Answer:
3. vertical stretch by a factor of 2; shift right 1 and down 1
4. shift left 4 and up 4 (no stretch or shrink)
Step-by-step explanation:
The vertex form equation is ...
y = a(x -h)^2 +k
It represents a vertical stretch of the parent function by a factor of 'a', a right shift of 'h', and an upward shift of 'k'.
Compare the the given equations to the above form to see the transformations.
__
3. (a, h, k) = (2, 1, -1) ⇒ vertical stretch by a factor of 2; shift right 1, down 1
4. (a, h, k) = (1, -4, 4) ⇒ no vertical stretch; shift left 4, up 4
the second duckling is wandering by 2.6 units distance than the first duckling .
<u>Step-by-step explanation:</u>
Here we have , Two ducklings wander away from the nest while their mother is away. The first duckling's displacement (distance and direction) from the nest is (12,5) The second duckling's displacement is (13,-8) . We need to find How much farther did the second duckling wander than the first duckling. Let's find out:
Let a = (12,5) and b =(13,-8)
The distance each duckling wandered is the magnitude of its displacement vector. Therefore, the expression Distance second duck wandered is given by :
⇒ 
⇒ 
⇒ 
⇒ 
⇒ 
Therefore , the second duckling is wandering by 2.6 units distance than the first duckling .
Answer:
thanks im not smart
Step-by-step explanation:
sn i knew that...