Answer:
<em><u>1.c</u></em>
<em><u>2.b</u></em>
<em><u>3.a</u></em>
<em><u>4.d</u></em>
<em><u>5.c</u></em>
Step-by-step explanation:
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Answer:
5 out of 12
5/12
January, March, May, June, July
There are three months whose name starts with the letter 'j': January, June, July
There are two months whose name starts with the letter 'm': March, May
So altogether, there are 5 months whose name starts with the letter 'j' or 'm'. So the possible outcome is 5 and total number of sample space is 12.
Therefore the required probability is: 5/12
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Answer:
This question requires a comparison between two different variables 6% and 16% values. If we let x=$ loaned on 6% loans and y=$ loaned on 16% loans, then we can relate two equations.
0.06x + 0.16y = $1500 --> referencing the interest earned from each percentage loaned.
x + y = $16000 --> referencing the total amount of money loaned out.
Rearrange either equation and substitute for a value in the other equation or use elimination to determine each individual variable.
Step-by-step explanation:
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:
And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
1/6×100%=50/3%
3/24×100%=25/4%
3/8×100%=75/2%
=>50/3%+25/4%+75/2%+x=100%
=>100%-725/12%=x
=>x=59 and 5/12
