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nikitadnepr [17]
3 years ago
11

How do I solve this equation?

Mathematics
1 answer:
frosja888 [35]3 years ago
4 0

Answer:

x=-3/11

Step-by-step explanation:

(x+3)/5 +2x=0

Multiply both sides by 5 to get rid of the fraction

5*( x+3)/5 +5*2x=0*5

x+3 + 10x =0

Combine like terms

11x +3 = 0

Subtract 3 from both sides

11x+3-3 =0-3

11x = -3

Divide by 11

11x/11 = -3/11

x = -3/11

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Positive angles located in the fourth quadrant may be described as___.
gladu [14]

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Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360 .</u>

The option is

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Step-by-step explanation:

When the terminal arm of an angle starts from the x-axis in the anticlockwise direction then the angles are always positive angles.

For Example.

Quadrant I    - 0 to 90°

Quadrant II   - 90° to 180°

Quadrant III  - 180° to 270°

Quadrant IV - 270° to 360° ( 4. 270≤Ф≤360  )

Hence,Positive angles located in the fourth quadrant may be described as<u> 270≤Ф≤360 .</u>

When the terminal arm of an angle starts from the x-axis in the clockwise direction than the angles are negative angles.

Quadrant IV  -          0° to -90°

Quadrant III   -      - 90° to -180°

Quadrant II    -      -180° to -270°

Quadrant I     -      -270° to -360°

5 0
3 years ago
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