To answer this
problem, we use the binomial distribution formula for probability:
P (x) = [n!
/ (n-x)! x!] p^x q^(n-x)
Where,
n = the
total number of test questions = 10
<span>x = the
total number of test questions to pass = >6</span>
p =
probability of success = 0.5
q =
probability of failure = 0.5
Given the
formula, let us calculate for the probabilities that the student will get at
least 6 correct questions by guessing.
P (6) = [10!
/ (4)! 6!] (0.5)^6 0.5^(4) = 0.205078
P (7) = [10!
/ (3)! 7!] (0.5)^7 0.5^(3) = 0.117188
P (8) = [10!
/ (2)! 8!] (0.5)^8 0.5^(2) = 0.043945
P (9) = [10!
/ (1)! 9!] (0.5)^9 0.5^(1) = 0.009766
P (10) = [10!
/ (0)! 10!] (0.5)^10 0.5^(0) = 0.000977
Total
Probability = 0.376953 = 0.38 = 38%
<span>There is a
38% chance the student will pass.</span>
Answer:
$12.60
Step-by-step explanation:
42/30%=42/0.3=$12.60
Brainleist plz
(comment if spelling is wrong anywhere)
<h3>
Answer: 7</h3>
The list of single digit primes is {2,3,5,7}. The largest prime is 7, so B = 7 is the largest possible value.
Also note how 707,747 rounds to 708,000 when rounding to 3 significant figures.
1) 
2) 
is a right angle (perpendicular lines form right angles)
3) 
is a right triangle (definition of a right triangle)
4) 
and 
are complementary (the acute angles of a right triangle are complementary)
Answer:
16+16
32
Step-by-step explanation:
