Hey there!
You can count from 668 to 900 using the following:
668 → 768 → 868 (two 100s)
868 → 878 → 888 → 898 (three 10s)
898 → 899 → 900 (two 1s)
Hope this helped you out! :-)
The general formula for the margin of error would be:
z * √[p (1-p) ÷ n]
where:
z = values for selected confidence level
p = sample proportion
n = sample size
Since the confidence level is not given, we can only solve for the
<span>√[p (1-p) ÷ n] part.
</span>
p = 44/70
n = 70
√[44/70 (1 - (44/70) ÷ 70]
√[0.6286 (0.3714)] ÷ 70
√0.2335 ÷ 70
√0.0033357 = 0.05775 or 0.058 Choice B.
2pm minus 30 minutes minus another 30 minutes, is 1pm.
2 schools is what lisa can attend
