Let us calculate the median; the 6th observation is 20, so it is 20. We need the 6th observation so that out of the 11 observations we have 5 above the median and 5 below (or equal). We also have that then Q1 is the median of the lowest 5 observations, hence 19 (14,16,19,19,20, the 3rd observation is 19). Similarly, we get that the median for the upper half of the observations, Q3 namely, is 22 (21,21,22,22,23, the 3rd observation is 22). Thus, the interquartile range is 3=Q3-Q1. According to our calculations, all observations are wrong.
I think it’s 121 because you have to plug in the x so like F(2)=(3^5)-1 = 121
Answer:
Step-by-step explanation:
![y = \frac{-1}{5}x - 4\\\\Plugin x = 0 , y = 0 - 4\\\\ y = -4\\\\(0 , -4)\\\\Plugin x = 5, y =\frac{-1}{5}*5-4 = -1-4=-5\\\\(5 , -5)\\\\Plugin x = -5, y =\frac{-1}{ 5}*(-5)-4=1 - 4 = -3\\(-5, -3)](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B-1%7D%7B5%7Dx%20-%204%5C%5C%5C%5CPlugin%20x%20%3D%200%20%20%2C%20y%20%3D%200%20-%204%5C%5C%5C%5C%20%20%20y%20%3D%20-4%5C%5C%5C%5C%280%20%2C%20%20-4%29%5C%5C%5C%5CPlugin%20x%20%3D%205%2C%20y%20%3D%5Cfrac%7B-1%7D%7B5%7D%2A5-4%20%3D%20-1-4%3D-5%5C%5C%5C%5C%285%20%2C%20-5%29%5C%5C%5C%5CPlugin%20x%20%3D%20-5%2C%20y%20%3D%5Cfrac%7B-1%7D%7B%205%7D%2A%28-5%29-4%3D1%20-%204%20%3D%20-3%5C%5C%28-5%2C%20-3%29)
Plot the points(0 ,-4) , (5 , -5) and (-5 , -3 ) in the graph and join the points.
Uhh uhh this might not be right so don’t listen but I think the answer is 46 or sum I’m sorry