3 years ago

Describe 58 as a sum of tens and ones

1 answer:

4 0

58 is 5 tens (5*10) and 8 ones (8*1)

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arlik [135]

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I am Lyosha [343]

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Fittoniya [83]

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olganol [36]

Answer: The number of letters that must be engraved for the costs to be the same is 125.

Step-by-step explanation:

Since we have given that

$0.4e+10+15=0.20e+5+25$

We need to find the number of letters.

$0.4e+25=0.2e+30\\\\0.4e-0.2e=30-25\\\\0.2e=25\\\\e=\dfrac{25}{0.2}\\\\e=125$

Hence, the number of letters that must be engraved for the costs to be the same is 125.

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3 years ago