Y= kx (k being a constant)
10= k × 4 k=5/2
y= 5x/2 The answer is C.
Answer:
35y2+13y−12
=35y2+28y−15y−12
=7y(5y+4)−3(5y+4)
=(7y−3)(5y+4)
Therefore, the possible length and breadth are 7y-3 units and 5y+4 units
Let
x--------> volume of 50% fertilizer
y--------> volume of 30% fertilizer
we know that
x+y=160-----> x=160-y-----> equation 1
x*0.5+y*0.3=160*0.4-----> equation 2
substitute equation 1 in equation 2
[160-y]*0.5+0.3*y=63.8----> 77-0.35*y+0.25*y=63.8
0.10*y=13.2------> y=13.2/0.10----> y=132 gal
x=220-y----> x=220-132----> x=88 gal
the answer is
88 gal of 50% fertilizer
132 gal 30% fertilizer