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Musya8 [376]
3 years ago
7

% growth Growth factor

Mathematics
1 answer:
Scorpion4ik [409]3 years ago
3 0

Answer:

growth factor for what?

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Is 90° an acute angle, right angle, obtuse<br> angle, or straight angle?
VashaNatasha [74]

Answer:

90 degrees is a right angle.

Step-by-step explanation:

|_

^ That would be a 90 degrees angle.

|

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|____

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Imagine this is a graph, that little square of the right would represent 90 degrees.

Angles less than 90 are acute angles, angles over 90 but under 180 degrees would be obtuse, and angles that are equal to 180 degrees are straight.

6 0
2 years ago
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Which property does the following<br> equation represent?<br> 62? + 43 = 43+ 6x2
timurjin [86]

Answer:

commutative

Step-by-step explanation:

you are typing the same numbers but in different order

8 0
3 years ago
I need help on this math problem ​
abruzzese [7]

Answer:

for the first one, simply add g(x) and h(x) :

x+3 + 4x+1 = 5x + 4

the second one, you would multiply them :

(x+3)(4x+1) = 4x^2 + 13x + 3

the last one, you would subtract :

(x+3)-(4x+1) = -3x + 2

and then substitute 2 for 'x' :

-3*2 + 2 = -6 + 2 = -4

8 0
2 years ago
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How to find imaginary zeros anf real zeros of F(x)=-4x^5-8x^3+12x​
Fofino [41]

Answer:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

Step-by-step explanation:

We are given the function:

f(x)=-4x^5-8x^3+12x

And we want to finds its zeros.

Therefore:

0=-4x^5-8x^3+12x

Firstly, we can divide everything by -4:

0=x^5+2x^3-3x

Factor out an x:

0=x(x^4+2x^2-3)

This is in quadratic form. For simplicity, we can let:

u=x^2

Then by substitution:

0=x(u^2+2u-3)

Factor:

0=x(u+3)(u-1)

Substitute back:

0=x(x^2+3)(x^2-1)

By the Zero Product Property:

x=0\text{ and } x^2+3=0\text{ and } x^2-1=0

Solving for each case:

x=0\text{ and } x=\pm\sqrt{-3}\text{ and } x=\pm\sqrt{1}

Therefore, our real and complex zeros are:

x=\{0, -1, 1, -i\sqrt{3}, i\sqrt{3}\}

4 0
2 years ago
Lois has a balance of $970 on a credit card with an APR of 24.2%, compounded monthly. About how much will she save in interest o
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