Please help me please

Mathematics

1 answer:

bulgar [2K]2 years ago

5 0

1) p-2
2)10.50
3)$30
4)c+3
5)$15

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a leaky faucet is losing water and is filling a 5-gallon bucket every 20 hours. At that rate, how many gallons of water will the

Arisa [49]

You can either scale down so you can get to 48 hours or just multiply from 20 to 48 and I'll explain both ways.
Scaling down:
You can find how many hours it takes to get to 1 gallon in the bucket by dividing
20÷5=4; It takes 4 hours to fill it up to one gallon.
You can now divide 48 by 4 to see how many gallons it'll take up to 48 hours.
48÷4=12
Quicker:
Divide 48 by 20;
48÷20=2.4
Now multiply since it filled it up to 5 gallons.
2.4×5=12
It'll fill 12 gallons in 48 hours.
Tell me if this helps!!

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2 years ago

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Morgan uses 1/4 of her supply of raisins to make trail mix and 3/8 of her supply of raisins to make cookies. If morgan uses 5 po

arlik [135]

First, we need to find the total fraction of her raisins she used:

1/4 + 3/8 = 2/8 + 3/8

She used 5/8 of her supply.

Knowing this:

5/8x = 5

We multiply by 8 (the LCD)

5x = 40

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Her supply was 8 pounds, and after making the food, she now has 3 pounds

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2 years ago

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Please help me out thank you.

natulia [17]

Answer:

the answer is D {-5, -13}

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2 years ago

What is greater 9,000 g or 8 kg

nikdorinn [45]

9000 grams is bigger

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2 years ago

A metallurgist has an alloy with 5% titanium and an alloy with 30% titanium. He needs 100 grams of an alloy with 15% titanium. H

andrey2020 [161]

Let us convert the percentages to decimal format first.. so 5% is just 5/100 or 0.05 and 15% is just 15/100 or 0.15

so hmmm, so, let's say it needs "x" amount and "y" amount of each respectively, so, whatever "x" and "y" are, they must add up to 100, and whatever their concentration is, must add up to what the mixture yields

thus

$\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{5\% alloy}&x&0.05&0.05x\\
\textit{30\% alloy}&y&0.30&0.3y\\
-----&-----&-------&-------\\
mixture&100&0.15&15
\end{array}
\\\\\\
\begin{cases}
x+y=100\implies \boxed{y}=100-x\\
0.05x+0.3y=15\\
----------\\
0.5x+0.3\left( \boxed{100-x} \right)=15
\end{cases}$

solve for "x"

what's "y"? well, y = 100 - x

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2 years ago