Answer:
Data set B would have flatter distribution with more data in each tail.
Step-by-step explanation:
We are given the following in the question:
Data set A has a smaller standard deviation than data set B.
Standard Deviation:
- It is a measure of dispersion of data.
- It tells us about how much the data deviates around the mean.
- It tells us about the overall deviation of the data from the mean.
- The standard deviation is small when the data are all close to the mean showing less variation.
- The standard deviation is larger when the data values are farther away from the mean, showing more variation.
Since data A has less standard deviation than data B, then data B has a flatter graphical representation as more of the data are present on the tails.
Answer: C
Step-by-step explanation:
Simplify to 4x^2 + 12x + 5 = 0 so that all the terms are on one side.
Do a part of the quadratic formula to see.
You only need to do the 
part. If it is negative, that means there are irrational solutions. If it is positive, it has two solutions. If it is 0, it has 1 solution.
It is positive so it has two solutions.
STEP-BY-STEP SOLUTION:
( x + 4 )^2 + y^2 = 22
x^2 + 2 × x × 4 + 4^2 + y^2 = 22
x^2 + 8x + 16 + y^2 = 22
y^2 = 22 - x^2 - 8x - 16
y^2 = - x^2 - 8x + 6
FINAL ANSWER:
Therefore, the answer is:
D. y^2 = - x^2 - 8x + 6
Please mark as brainliest if you found this helpful! :)
Thank you <3
9514 1404 393
Answer:
77/85
Step-by-step explanation:
<u>Given</u>:
cos(A) = 4/5
sin(B) = 15/17
<u>Find</u>:
cos(A-B)
<u>Solution</u>:
From your knowledge of Pythagorean triples, you know that one of them is (3, 4, 5) and another is (8, 15, 17). Using your imagination, or by drawing the triangles, you can determine the needed trig functions to be ...
sin(A) = 3/5
cos(B) = 8/17
__
Alternatively, you can use the Pythagorean identity to find ...
sin(A) = √(1 -cos²(A)) = √(1 -(4/5)²) = √(9/25) = 3/5
cos(B) = √(1 -sin²(B)) = √(1 -(15/17)²) = √(64/289) = 8/17
__
Then application of the angle difference formula is straightforward.
cos(A -B) = cos(A)cos(B) +sin(A)sin(B)
cos(A -B) = (4/5)(8/17) +(3/5)(15/17) = (32 +45)/85
cos(A -B) = 77/85
_____
Some graphing calculators can express the result ...
cos(arccos(4/5) -arcsin(15/17)) ≈ 0.90588235294
... as the fraction 77/85
