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Rama09 [41]
2 years ago
9

Which equation best matches the graph shown below?

Mathematics
1 answer:
n200080 [17]2 years ago
6 0

Answer:

y= 0.2(x+1)^2+5 (Bottom left answer)

Step-by-step explanation:

Hope this helps :)

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Is 4/8 bigger or smaller than 1/2
jeka94
There are the same because 4/8 is rudeced to 1/2
8 0
3 years ago
Read 2 more answers
If QS bisects PQT, SQT=(8x- 25),PQT=(9x+34), and SQR=112, find each measure.
Goryan [66]

The values of the angles are; x = 12°, m∠PQS = 71°, m∠PQT = 142° and m∠TQR = 41°

<h3>What are the measure of the each angle?</h3>

The required angles; x, m∠PQS, m∠PQT, and m∠TQR

The given parameters are bisects ∠PQT

m∠SQT = (8·x - 25)°

m∠PQT = (9·x + 34)°

m∠SQR = 112°

We have;

m∠PQT = m∠SQT + m∠PQS (Angle addition postulate)

m∠SQT ≅ m∠PQS (Angles formed by angle bisector are congruent)

m∠SQT = m∠PQS  by Definition of congruency

m∠PQT = 2 × m∠SQT

Therefore;

(9·x + 34)° = 2 × (8·x - 25)° = (16·x - 50)°

Collecting like terms gives:

(34 + 50)° = 16·x - 9·x = 7·x

7·x = 84°

x = 84°/7 = 12°

x = 12°

m∠SQT = (8·x - 25)°

Therefore;

m∠SQT = (8 × 12 - 25)° = 71°

m∠SQT = 71°

m∠PQT = 2 × m∠SQT

∴ m∠PQT = 2 × 71° = 142°

m∠PQT = 142°

m∠PQS = m∠SQT (Angles formed by the same bisector )

∴ m∠PQS = m∠SQT = 71°

m∠PQS = 71°

m∠SQR = m∠SQT + m∠TQR (Angle addition postulate)

m∠SQT = 71°

∴  m∠SQR = 112° = 71° + m∠TQR

m∠TQR = 112° - 71° = 41°

m∠TQR = 41°

Learn more about angles here:

brainly.com/question/2882938

#SPJ1

4 0
1 year ago
How to do this, please help me
Nataly_w [17]
Idk if the answer is correctly

6 0
3 years ago
Please help!<br><br> Add using a number line<br><br> −2/5 +4/5 = ?
kobusy [5.1K]

-  \frac{2}{5}  +  \frac{4}{5}  =  \frac{2}{5}
5 0
3 years ago
(4m-1)(m+2) Find Products<br> (With Work Please!)
katrin2010 [14]

Answer:

3m times 2m = 1m

Step-by-step explanation:

because 4m- 1 =3m and m+2 =2m

5 0
2 years ago
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