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gavmur [86]
3 years ago
8

Find the perimeter of a triangle with sides 12inches, 9inches, and 15inches

Mathematics
1 answer:
ololo11 [35]3 years ago
3 0
12+9+15=36 cm. perimeter is basically all the sides added up together
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$30 is taken off the price of a dress. If the new price is now 60% off the original price, what was the original price of the dr
Alex Ar [27]
The original price of the dress is $75
3 0
2 years ago
Plz answer all these questions for me I really need help
Ber [7]
A is 400

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4 0
3 years ago
What is the base of a triangle with a height of 14 cm and an area of 42 square cm?
sasho [114]

Answer:

6cm

Step-by-step explanation:

area =  \frac{1}{2} \times  base \times  height \\ 42 =  \frac{1}{2}  \times b \times 14 \\ 42 =  \frac{14b}{2}  \\ 42 = 7b \\  \frac{42}{7}  =  \frac{7b}{7}  \\ base = 6cm

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em>

5 0
3 years ago
Read 2 more answers
Solve the system by using a matrix equation (Picture provided)
Katyanochek1 [597]

Answer:

Option b is correct (8,13).

Step-by-step explanation:

7x - 4y = 4

10x - 6y =2

it can be represented in matrix form as\left[\begin{array}{cc}7&-4\\10&-6\end{array}\right] \left[\begin{array}{c}x\\y\end{array}\right] = \left[\begin{array}{c}4\\2\end{array}\right]

A= \left[\begin{array}{cc}7&-4\\10&-6\end{array}\right]

X= \left[\begin{array}{c}x\\y\end{array}\right]

B= \left[\begin{array}{c}4\\2\end{array}\right]

i.e, AX=B

or X= A⁻¹ B

A⁻¹ = 1/|A| * Adj A

determinant of A = |A|= (7*-6) - (-4*10)

                                    = (-42)-(-40)

                                    = (-42) + 40 = -2

so, |A| = -2

Adj A=  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]

A⁻¹ =  \left[\begin{array}{cc}-6&4\\-10&7\end{array}\right]/ -2

A⁻¹ =  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right]

X= A⁻¹ B

X=  \left[\begin{array}{cc}3&-2\\5&-7/2\end{array}\right] *\left[\begin{array}{c}4\\2\end{array}\right]

X= \left[\begin{array}{c}(3*4) + (-2*2)\\(5*4) + (-7/2*2)\end{array}\right]

X= \left[\begin{array}{c}12-4\\20-7\end{array}\right]

X= \left[\begin{array}{c}8\\13\end{array}\right]

x= 8, y= 13

solution set= (8,13).

Option b is correct.

3 0
3 years ago
10. If 1000 cm = 1 l, find the capacity of the following water tank in litre
Lelu [443]
<h2>Given :</h2>

  • length = 200 cm

  • breadth = 150 cm

  • height = 100 cm

<h2>Solution : </h2>

\large \boxed{volume = l \times b \times h}

  • 200 \times 150 \times 100

  • 3000000  \: \: cm {}^{3}

Through the statement above we have,

  • \small\mathrm{1000  \: cm³ = 1  \:  \: }l

  • \small\mathrm{1 \: cm {}^{3}  =  \dfrac{1}{1000} \: }l

  • \small\mathrm{3000000 \: cm {}^{3}  = 3000000 \times  \dfrac{1}{1000}  \: }l

  • \small\mathrm{3000000 \: cm {}^{3}  = 3000000 \times  \dfrac{1}{1000}  \: }l

  • \small\mathrm{ 3000 \:  \: litres}

_____________________________

\mathrm{ \#TeeNForeveR}

3 0
3 years ago
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