We keep the 2x^2 because we can only subtract something from that if it also is squared. From there, we subtract the 7x from 2x^2-11. Since there is no previous x's in the 2x^2-11, we just make it -7x. So, without even continuing the problem, we see that A) is the correct answer because it is the only one with -7x.
k, n - integers
2k+1 - an odd integer
2n+1 - another odd integer
The product of them:
(2k + 1)(2n + 1) =
= 4kn + 2k + 2n + 1 =
= 2(2kn + k + n) + 1
The product of integers (2kn) is integer
and the sum of them (2kn+k+n) also is integer
So (2k + 1)(2n + 1) = 2(2kn + k + n) + 1 is an odd integer
The pentagon has a sum of interior angles of 540 degrees.
Therefore,
(4x + 5) + (5x - 5) + (6x + 10) + (4x + 10) + 7x = 540;
26x = 520;
x = 20;
Answer:
The slope that is perpendicular to the line will be:
Step-by-step explanation:
Given the equation
We know that
is the slope-intercept form of a line where m is the slope and b is the y-intercept.
So, writing the equation in the slope-intercept form
here
∵
As we know that for perpendicular lines, one slope is the negative reciprocal of the other.
Therefore, the slope that is perpendicular to the line will be:
Answer:
It would be y=12x
Step-by-step explanation:
I think
