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RSB [31]
3 years ago
15

What is the point of intersection when the system of equations below is graphed on a coordinate plane? X-y=1 y-x=1

Mathematics
1 answer:
VMariaS [17]3 years ago
6 0
Lets reorder the equations

y = x - 1         (1)
y = x +1         (2)

Since both lines have the same slope  (m = 1), then this is an inconsistent system with NO solution

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Does any one know how to do this. It would be such a life saver if you could help me out. Thx
Aneli [31]

Answer:

1: (3 ,- 4)

2:up (a > o)

3: -4

4: 2 units to the right

5: 4 units down

6: y = (x-2)^2-4

7:

8:

9: (5,9)

10: x=5

11: (4,7) and (6,7)

12:

Step-by-step explanation:

I'm not sure if you wanted it explained or answered , so i just answered most of them. Sorry if you wanted it explained.

3 0
2 years ago
2/3 x 2 1/3 = what is the awsner to this
topjm [15]

Answer:

1 5/9

Step-by-step explanation:

3 0
3 years ago
HELPPPPPPP PLEASEEEEEEEEEEE
Inessa [10]

Answer:

y=-1

Step-by-step explanation:

it is a straight line graph with no gradient therefore no X value. It crosses the y axis at -1

8 0
3 years ago
Please solve the eqution<br> Cos4x + cos2x - 2 =0
horrorfan [7]

cos4x = cos2x

We know that:

cos2x = 1-2cos^2 x

==> cos4x = 1-2cos^2 (2x)

Now substitute:

==> 1-2cos^2 (2x) = cos2x

==> 2cos^2 (2x) + cos2x - 1 = 0

Now factor:

==> (2cos2x -1)(cos2x + 1) = 0

==> 2cos2x -1 = 0 ==> cos2x =1/2 ==> 2x= pi/3

==> x1= pi/6 , 7pi/6

==> x1= pi/6 + 2npi

==> x2= 7pi/6 + 2npi

==> cos2x = -1 ==> 2x= pi ==> x3 = pi/2 + 2npi.

<span>==> x= { pi/6+2npi, 7pi/6+2npi, pi/2+2npi}</span>

6 0
3 years ago
A circle has a diameter with endpoint at 5 + 18i and -3 + 2i. What is the center of the circle?
Alexus [3.1K]
So there is a real and imaginary axis
the midopint is just the average of them
average between the reals is (5-3)/2=2/2=1
average between imaginaries is (18i+2i)/2=20i/2=10i

center is 1+10i
7 0
3 years ago
Read 2 more answers
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