Answer:
We conclude that the plant should shut down.
Step-by-step explanation:
We are given the following in the question:
Population mean, μ = 60
Sample mean,
= 61.498
Sample size, n = 100
Alpha, α = 0.05
Population standard deviation, σ = 6
a) First, we design the null and the alternate hypothesis such that the power plant will be shut down when the null hypothesis is rejected.
We use One-tailed(right) z test to perform this hypothesis.
b) Formula:
Putting all the values, we have
Now,
Since,
We reject the null hypothesis and accept the alternate hypothesis. Thus, the temperature of waste water discharged is greater than 60°F. We conclude that the power plant will shut down.
Calculating the p-value from the z-table:
P-value = 0.0063
Since,
P-value < Significance level
We reject the null hypothesis and accept the alternate hypothesis. Thus, the temperature of waste water discharged is greater than 60°F. We conclude that the power plant will shut down.
Double every year
year one
4 times 2
year 2
4 times 2 times 2 aka 4 times 2^2
year 3
4 times 2 times 2 times 2 aka 4 times 2^3
obviously
at year 'n' the number of rabbits will be
4 times 2^n
10 + 3 + 2/100 + 6/1000
hope it helps!
You can dispose a number
of elements in a matrix-like formation with
shape if and only if
and
both divide
, and also
.
So, we need to find the greatest common divisor between
and
, so that we can use that divisor as the number of columns, and then.
To do so, we need to find the prime factorization of the two numbers:


So, the two numbers share only one prime in their factorization, namely
, but we can't take "too many" of them:
has "three two's" inside, while
has "five two's" inside. So, we can take at most "three two's" to make sure that it is a common divisor. As for the other primes, we can't include
nor
, because it's not a shared prime.
So, the greater number of columns is
, which yield the following formations:

