D = rt. The first car's rate is r, and the other one, going faster, is r + 12. The time they travel is 2 hours. Since one is going faster than the other, he has gotten farther. But, regardless of that, the distance between them is 232. So the distance the first one travels, r*t, which 2r, plus the distance the second one travels, 2(r+12) = 232. 2r + 2r + 24 = 232. Solve for r. 4r = 208 and r = 52. The slower one goes 52 and the faster one goes 64
Answer:
<h2>4</h2>
Step-by-step explanation:
(-35-42-63)/7= (-140)/7=-20
Answer:
x=1 is the solution of the equation 2x+4=10−4x
Step-by-step explanation:
The graphs of f(x)=2x+4 and g(x)=10−4x intersect at (1, 6)
2x +4 = 10 - 4x
We need to solve for x by combining like terms
Add 4x on both sides
6x + 4= 10
Now subtract 4 on both sides
6x = 6
divide both sides by 6
x= 1
x=1 is the solution of the equation 2x+4=10−4x
