The answer for your question is B
Let x = roller coaster ticket
let y = boat ride ticket
x + y = 10
4x + 3y = 37
x = 10 - y
4x + 3y = 37
4(10-y) + 3y = 37
40 - 4y + 3y = 37
-y = 37 - 40
-y = -3
y = -3/-1
y = 3
x = 10 - y
x = 10 - 3
x = 7
x = 7 ; y = 3
4x + 3y = 37
4(7) + 3(3) = 37
28 + 9 = 37
37 = 37
X + x + 3(2+x)= 36
2x + 6 + 3x = 36
5x + 6 = 36
5x = 36 - 6
5x = 30
x = 6
Longer piece = 2 + 6 = 8inches
Answer:
Step-by-step explanation:
We can write two equations in the two unknowns using the given relations. Let g and b represent the costs of a round of golf and a turn in the batting cage, respectively.
5g +4b = 60 . . . . . Sylvester's expense
3g +6b = 45 . . . . . Lin's expense
Dividing the second equation by 3 gives ...
g +2b = 15 ⇒ 2b = 15 -g
Substituting into the first equation, we have ...
5g +2(2b) = 60
5g +2(15 -g) = 60 . . . . . substitute for 2b
3g = 30 . . . . . . . . . subtract 30, collect terms
g = 10 . . . . . . . divide by 3
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2b = 15 -10 = 5 . . . . use the value of g to find b
b = 2.5 . . . . . . . . divide by 2
Mini golf costs $10 per round; batting cages cost $2.50 per turn.
