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3 years ago

What's the algebraic expression of "the product of 3x and (3x1) is at least 35

1 answer:

5 0

$3x(3x) \geq 35 \\\frac{9x^{2}}{9} \geq \frac{35}{9} \\x^{2} \geq \frac{35}{9} \\\sqrt{x^{2}}\geq \sqrt{\frac{35}{9}} \\x \geq \frac{\sqrt{35}}{\sqrt{9}} \\x \geq \frac{\sqrt{35}}{3}
\≥$

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Triangle ABC is similar to triangle PQR, as shown below:

natita [175]

Answer:

$\frac{q}{b}=\frac{r}{c}$

Step-by-step explanation:

Consider the options for this question are as follow,

$\frac{q}{c}=\frac{r}{b}$

$\frac{c}{p}=\frac{b}{a}$

$\frac{c}{a}=\frac{q}{r}$

$\frac{q}{b}=\frac{r}{c}$

Here, In triangles ABC and PQR,

AB = c, BC = a, AC = b, PQ = r, QR = p and PR = q,

Since,

$\traingle ABC\sim \triangle PQR$

We know that,

The corresponding sides of similar triangles are in same proportion,

Thus,

$\frac{AB}{PQ}=\frac{BC}{QR}=\frac{AC}{PR}$

$\frac{c}{r}=\frac{a}{p}=\frac{b}{q}$

$\frac{r}{c}=\frac{p}{a}=\frac{q}{b}$

$\implies \frac{q}{b}=\frac{r}{c}$

3 0

3 years ago

Read 2 more answers

PLEASE NO LINKS Thank you :)

alexgriva [62]

Answer:

hon you never asked a question or added an image. id be happy to try and help if you do!

6 0

3 years ago

Read 2 more answers

Find the values of the apple, banana and lollypop below.<br><br> Pls help

maks197457 [2]

Answer:

a= Apple = 3

b= Banana =5

v= Lollypop=1

Step-by-step explanation:

36 is divided into 2 giving us 18

Let apple=a

Banana=b

Lollypop=c

In the first half

An apple + 3 bananas=18

a+3b=18 (1)

Second half is further divided into 2

That is,

18÷2=9

First half of the second half

3apples=9

3a=9 (2)

Second half of the second half

1 apple + 1 banana + 1 lollypop=9

a+b+c=9 (3)

a+3b=18 (1)

3a=9 (2)

a+b+c=9 (3)

From (2)

3a=9

Divide both sides by 3

a=9/3

a=3

Substitute a=3 into 1

a+3b=18

3+3b=18

3b=18-3

3b=15

Divide both sides by 3

b=15/3

b=5

Substitute the value of a and b into (3)

a+b+c=9

3+5+c=9

8+c=9

c=9-8

c=1

Therefore,

a= Apple = 3

b= Banana =5

v= Lollypop=1

6 0

4 years ago

The physical plant at the main campus of a large state university recieves daily requests to replace florecent lightbulbs. The d

zaharov [31]

Answer:

P(61≤ X≤94) = 49.85%

Step-by-step explanation:

From the given information:

The mean of the bell shaped fluorescent light bulb μ = 61

The standard deviation σ = 11

The objective of this question is to determine the approximate percentage of light bulb replacement requests numbering between 61 and 94 i.e P(61≤ X≤94)

Using the empirical (68-95-99.7)rule ;

At 68% , the data lies between μ - σ and μ + σ

i.e

61 - 11 and 61 + 11

50 and 72

At 95%, the data lies between μ - 2σ and μ + 2σ

i.e

61 - 2(11) and 61 + 2(11)

61 - 22 and 61 +22

39 and 83

At 99.7%, the data lies between μ - 3σ and μ + 3σ

i.e

61 - 3(11) and 61 + 3(11)

61 - 33 and 61 + 33

28 and 94

the probability equivalent to 94 is when P(28≤ X≤94) =99.7%

This implies that ,

P(28≤ X≤94) + P(61≤ X≤94) = 99.7%

P(28≤ X≤94) = P(61≤ X≤94) = 99.7 %

This is so because the distribution is symmetric about the mean

P(61≤ X≤94) = 99.7 %/2

P(61≤ X≤94) = 49.85%

5 0

3 years ago

Find the sum 1/b^2c +b/c^2

inysia [295]

Hey! here is the answer
<u>b³+c
</u>b²c²

8 0

3 years ago