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valina [46]
1 year ago
6

Translate pre-image coordinates Help me with 4 and 6 please!!

Mathematics
1 answer:
Alecsey [184]1 year ago
8 0

4. Because there is already a rule that they gave us, we can apply it to each point to find the post image coordinates.

The rules are (x-13) and (y+21).

We can substitute each point's x and y coordinates into the x and y values in the rules.

A: (3, -5) --> after substituting, (3-13), (-5+21)

simplify: (-10, 16)

B: (10, -8) --> after substituting, (10-13), (-8+21)

simplify: (-3, 13)

C: (12, -13) --> after substituting, (12-13), (-13+21)

simplify: (-1, 8)

D: (5, -10) --> after substituting, (5-13), (-10+21)

simplify: (-8, 11)

Final Coordinates:

A'= (-10, 16)

B'= (-3, 13)

C'= (-1, 8)

D'= (-8, 11)

6. We can apply the same concept as problem 4, but we have to make our own rules. We know that we have to translate to the right 14 units and up 13 units. Going to the right 14 units is adding 14 to x, so our rule is (x+14). Going up 13 units is adding 13 to y, so our rule is (y+13). A rule to use when you're not sure whether it's x, y, positive or negative is this:

When the problem says,

right: add to x

left: subtract from x

up: add to y

down: subtract from y

Now that we have our rules, we can solve. Use the same method as problem 4, and substitute our original points into the rules to get our new points.

A: (-12, 3) --> after substituting, (-12+14), (3+13)

simplify: (2, 16)

B: (-6, 3) --> after substituting, (-6+14), (3+13)

simplify: (8, 16)

C: (-12, 9) --> after substituting, (-12+14), (9+13)

simplify: (2, 22)

Final Coordinates:

A'= (2, 16)

B'= (8, 16)

C'= (2, 22)

hope this helped! comment if something doesn't make sense and i'll try to explain as best as i can. have a nice day!

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Answer:

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Step-by-step explanation:

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<em>Comment on "cross multiply"</em>

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

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Step-by-step explanation:

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