Number 1 is answer 1 Number 2 is answer 3 Number 3 is answer 4
Ok so we'll go ahead and solve for y first - we just need to get it alone on one side of the equal sign
Step 1: subtract 2x from each side
2x - 7y - 2x = 19 - 2x
This cancels out the 2x on the left, giving us
-7y = 19 - 2x
Step 2: divide both sides by -7
=
+ 
This gives us
y = -19/7 + 2x/7
That should be your answer for the first question. Now solving the next parts are easy. All you need to do is plug in x.
When x = -3
y = -19/7 + 2x/7
y = -19/7 + 2(-3)/7
y = -19/7 - 6/7
y = -25/7
When x = 0
y = -19/7 + 2x/7
y = -19/7 + 2(0)/7
y = -19/7
When x = 3
y = -19/7 + 2x/7
y = -19/7 + 2(3)/7
y = -19/7 + 6/7
y = -13/7
Hope that helps! Feel free to ask if I can help with anything else :)
The solutions of the quadratic equation x² - 5x - 36 = 0 are -4 and 9.
The graph is attached below.
- We are given a quadratic function.
- A polynomial equation of degree two in one variable is a quadratic equation.
- The function given to us is :
- y = x² - 5x - 36
- We need to find the solution of the quadratic function.
- To find the roots, let y = 0.
- x² - 5x - 36 = 0
- Use the quadratic formula.
- In elementary algebra, the quadratic formula is a formula that gives the solution(s) to a quadratic equation.
- x = [-b±√b²-4ac]/2a
- x = [-(-5) ± √25 - 4(1)(-36)]/2(1)
- x = (5 ± √25 + 144)/2
- x = (5 ± √169)/2
- x = (5 ± 13)/2
- x = 9 or x = -4
To learn more about functions, visit :
brainly.com/question/12431044
#SPJ1
Here are the step for solving this:
1. 3y + 5 > 23
-5 -5
3y/3 > 18/3
y > 6
In words what you are doing is getting y by itself on one side. Subtract the 5 to undo the adding of 5 first. Then, divide both sides by 3.