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AVprozaik [17]
3 years ago
7

Kevin can travel 22 and a half miles in one third hour what is his average speed in miles per hour

Mathematics
2 answers:
frutty [35]3 years ago
5 0
His average speed is 67 1/2 miles per hour. 22.5 in each 1/3 of an hour. So, multiply that by 3 and get 67 1/2 miles in each whole hour.
dalvyx [7]3 years ago
4 0
If it's 1/3 of an hour then we multiply it by 3 so 22.5 x 3 is 67.5 
Answer: 67.5 m/h
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when a jug is 1/5 full and it weighs 250 grams next it 4/5 full and weighs 550 grams what is the weight of the jug?
AleksAgata [21]
X=weight of the jug
y=witht of liquid when the jug is full
we suggest this system of equations:
x+y/5=250
x+4y/5=550
we solve this system of equations by equalization method. 
x=250-y/5
x=550-4y/5
250-y/5=550-4y/5
least common multiple=5
1250-y=2750-4y
-y+4y=2750-1250
3y=1500
y=1500/3
y=500 

x=250-y/5
x=250-500/5
x=250-100
x=150

Answer: weight of the jug = 150grams. 
7 0
3 years ago
Read 2 more answers
A youth group has a yard sale to raise money for a charity. The group earns $800 but decides to put its money in the
marysya [2.9K]

Answer:

see explanation below

Step-by-step explanation:

In this case, I don't know if the 4% rate is annual, so I'm going to assume that it's annual.

The other thing that I will assume is that this increase is constant but every year you get 4% interest of the amount that you have by the end of the year, and not 4% of the initial amount. However, I will do it by the two methods just in case.

If the amount is increased 4% every year then:

P = Po * (IV)^n

where n: year

To get the index variation (IV):

IV = 4/100 = 0.04, and we also know that every year is increased so:

1 + 0.04 = 1.04

Now let's get the money after 3 years:

P = 800 * (1.04)^3 = 899.89 $ or simply 900$

If the amount is increased 4% but over the initial amount always:

let's calculate the 4% of 800:

800 * 0.04 = 32

The first year it would be:

800 + 32 = 832 $

second year:

832 + 32 = 864$

third year: 864 + 32 = 896$

So, for the first assumption we get 900$ and the second assumption we get 896$.

4 0
3 years ago
Solve for v -5v-17>2v+11
V125BC [204]

Answer:

Step-by-step explanation:

7 0
3 years ago
Condense the following logs into a single log:
mamaluj [8]

QUESTION 1

The given logarithm is

8\log_g(x)+5\log_g(y)

We apply the power rule of logarithms; n\log_a(m)=\log_(m^n)

=\log_g(x^8)+\log_g(y^5)

We now apply the product rule of logarithm;

\log_a(m)+\log_a(n)=\log_a(mn)

=\log_g(x^8y^5)

QUESTION 2

The given logarithm is

8\log_5(x)+\frac{3}{4}\log_5(y)-5\log_5(z)

We apply the power rule of logarithm to get;

=\log_5(x^8)+\log_5(y^{\frac{3}{4}})-\log_5(z^5)

We apply the product to obtain;

=\log_5(x^8\times y^{\frac{3}{4}})-\log_5(z^5)

We apply the quotient rule; \log_a(m)-\log_a(n)=\log_a(\frac{m}{n} )

=\log_5(\frac{x^8\times y^{\frac{3}{4}}}{z^5})

=\log_5(\frac{x^8 \sqrt[4]{y^3} }{z^5})

7 0
3 years ago
5x+17=-8 solve the equation
kirill115 [55]

5x=-8-17

5x=-25

x=-25/5

x=-5

7 0
3 years ago
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