Let the three numbers be x, y, and z.
If the sum of the three numbers is 3, then x+y+z=3
If subtracting the second number from the sum of the first and third numbers gives 9, then x+z-y=9
If subtracting the third number from the sum of the first and second numbers gives -5, then x+y-z=-5
This forms the system of equations:
[1] x+y+z=3
[2] x-y+z=9
[3] x+y-z=-5
First, to find y, let's take do [1]-[2]:
x+y+z=3
-x+y-z=-9
2y=-6
y=-3
Then, to find z, let's do [1]-[3]:
x+y+z=3
-x+-y+z=5
2z=8
z=4
Now that you have y and z, plug them into [1] to find x:
x+y+z=3
x-3+4=3
x=2
So the three numbers are 2,-3, and 4.
Answer:



Step-by-step explanation:
Given


maximum
minimum
Required
Solve graphically
First, we need to determine the inequalities of the system.
For number of coins, we have:
because the number of coins is not less than 20
For the worth of coins, we have:
because the worth of coins is not more than 0.80
So, we have the following equations:


Make y the subject in both cases:


Divide through by 0.01



The resulting inequalities are:


The two inequalities are plotted on the graph as shown in the attachment.
--- Blue
--- Green
Point A on the attachment are possible solutions
At A:

Procedure:
1) calculate the number of diferent teams of four members that can be formed (with the ten persons)
2) calculate the number of teams tha meet the specification (two girls and two boys)
3) Divide the positive events by the total number of events: this is the result of 2) by the result in 1)
Solution
1) the number of teams of four members that can be formed are:
10*9*8*7 / (4*3*2*1) = 210
2) Number of different teams with 2 boys and 2 girls = ways of chosing 2 boys * ways of chosing 2 girls
Ways of chosing 2 boys = 6*5/2 = 15
Ways of chosing 2 girls = 4*3/2 = 6
Number of different teams with 2 boys and 2 girls = 15 * 6 = 90
3) probability of choosing one of the 90 teams formed by 2 boys and 2 girls:
90/210 = 3/7
A=50000(1.025^t), B=50000+3000t
A(10)=$64004.23, B(10)=$80000
So Brock will be earning $15995.77 more than Adam in the tenth year.
53.778 is the answer. I hope this helps and have a good day!